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a) 10 - x : 2 = 1
x: 2 = 9
x = 18
b) x:4 + 3 x 2 = 7
x:4 + 6 = 7
x:4 = 1
x = 4
c) 2: x + 5 = 6
2: x = 1
x = 2
+4.10-x:2=1
40-x:2=1
x:2=40-1
x:2=39
x:2=19,5
+5.x:4+3*2=7
5.x:4+6=7
5.x:4=7-6=1
5.x=1.4=4
x=4:5
x=0,8
+6.2:x+5=6
12:x=6-5
12:x=1
x=12:1
x=12
+7.2*x*3*5=30
14.x.15=30
14.x=2
x=2:14
x=1/7
+8.2*x:10*2=1
16.x:20=1
16.x=20
x=20:16
x=1,25
9.18:x-5*2=8
10.5*5-2:x=24
\(4) 10-x:2=1 \)
\(=> x:2=10-1\)
\(=> x:2=9\)
\(=> x=9.2\)
\(=> x=18\). Vậy \(x=18\)
\(5) x:4+3.2=7\)
\(=> x:4+6=7\)
\(=> x:4=7-6\)
\(=> x:4=1\)
\(=> x=4\). Vậy \(x=4\)
\(6) 2:x+5=6\)
\(=> 2:x=6-5\)
\(=> 2:x=1\)
\(=> x=2\).Vậy \(x=2\)
\(7) 2.x.3.5=30\)
\(=> 2x.15=30\)
\(=>2x=30:15\)
\(=> 2x=2\)
\(=> x=1\).Vậy \(x=1\)
\(8)2.x:10.2=1\)
\(=> 2x=1:2.10\)
\(=> 2x=5\)
\(=>x=5:2\)
\(=> x=\frac{5}{2}\).Vậy \(x=\frac{5}{2}\)
\(9)18:x-5.2=8\)
\(=> 18:x-10=8\)
\(=>18:x=8+10\)
\(=>18:x=18\)
\(=> x=1\).Vậy \(x=1\)
\(10)5.5-2:x=24\)
\(=>25-2:x=24\)
\(=> 2:x=25-24\)
\(=>2:x=1\)
\(=>x=2\).Vậy \(x=2\)
1.Ta có:
Ư(10)={1;2;5;10}.
Ư(20)={1;2;4;5;10;20}.
=> Ư(10;20)={1;2;5;10}
Cái dấu ^ là gì rồi tôi giải tiếp cho
\(\frac{3^{10}.11+3^{10}.10}{3^9.2^4}\)
\(=\frac{3^{10}.\left(11+10\right)}{3^9.2^4}=\frac{3^{10}.21}{3^9.16}\)
\(=\frac{3.21}{16}=\frac{63}{16}\)
Câu 1 xem kỉ đề
\(B,\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5-2.49^5}=\frac{7^{12}.5-7^{11}}{7^{10}.5-2.7^{10}}=\frac{7^{11}.\left(7.5-1\right)}{7^{10}.\left(5-2\right)}=\frac{7.34}{3}=\frac{238}{3}\)
a) A=212.35-\(\frac{2^{12}.3^6}{2^{12}}\)+93+84.35
=212.35-36+36+212.35
=213.35
b)B=496.5-5.\(\frac{7^{11}}{\left(-7\right)^{10}}-2.49^5\)
=496.5-7.5-2.495
=712.5-7.5-2.710
3^10.11 + 3^10.5 : ( 3^9.2^4)
=3^10.(11+5) : (3^9.2^4)
=(3^10.16) : (3^9.16)
=3^10 : 3^9
=3
Có gì sai thì góp ý cho mình nhé, Tks ! :)))
\(C=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.\left(11+5\right)}{3^9.2^4}=\frac{3^{10}.16}{3^9.16}=\frac{3^{10}}{3^9}=3\)
\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.16}{3^9.16}=3\)
\(B=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.78}{2^8.104}=\frac{2^{10}.26.3}{2^8.2^2.26}=3\)
\(C=\frac{72^3.52^4}{108^4}=\frac{\left(3^2.2^3\right)^3.\left(13.2^2\right)^4}{\left(3^3.2^2\right)^4}=\frac{3^6.2^9.13^4.2^8}{3^{12}.2^8}=\frac{2^9.13^4}{3^6}\)
\(D=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(33-1\right)}{2^2.3^{28}}=\frac{3^{29}.2^5}{2^2.3^{28}}=3.8=24\)
$2x+4x=10.5+4$
$(2+4).x=50+4$
$6x=54$
$x=54:6$
$x=9$