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1) \(\frac{5}{8}.\frac{7}{3}-\frac{5}{2}.\frac{1}{8}=\frac{5}{8}.\frac{7}{3}-\frac{5}{8}.\frac{1}{2}=\frac{5}{8}\left(\frac{7}{3}-\frac{1}{2}\right)=\frac{5}{8}.\frac{11}{6}=\frac{55}{48}\)
2) \(\frac{21}{10}.\frac{3}{4}-\frac{21}{10}.\frac{3}{4}=\frac{21}{10}\left(\frac{3}{4}-\frac{3}{4}\right)=\frac{21}{10}.0=0\)
3) \(\frac{-4}{11}:\frac{-6}{11}=\frac{-4}{11}.\frac{-11}{6}=\frac{-4.\left(-11\right)}{11.6}=\frac{-4.\left(-1\right)}{1.6}=\frac{4}{6}=\frac{2}{3}\)
4)\(\frac{2}{7}.\frac{14}{3}-1=\frac{2.14}{7.3}-1=\frac{2.2}{1.3}-1=\frac{4}{3}-1=\frac{1}{3}\)
5)\(\frac{4}{7}:\left(\frac{1}{5}.\frac{4}{7}\right)=\frac{4}{7}:\frac{4}{35}=\frac{4}{7}.\frac{35}{4}=\frac{4.35}{7.4}=\frac{1.5}{1.1}=5\)
6) \(\frac{12}{7}.\frac{7}{4}+\frac{35}{11}:\frac{245}{121}=\frac{12.7}{7.4}+\frac{35}{11}.\frac{121}{245}=\frac{3.1}{1.1}+\frac{35}{11}.\frac{121}{245}=3+\frac{35}{11}.\frac{121}{245}=3+\frac{35.121}{11.245}=\frac{1.11}{1.7}=\frac{11}{7}\)
a: =-5-7-8-3=-26
b: =-4-2-5-6=-17
c: =-8-11-4-2=-25
d: -9-15-6-3=-30
e: =-12-9-3-8=-32
các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha
a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)
-\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)
-6 < \(x\) < -4
vì \(x\) \(\in\) Z nên \(x\) = -5
A=\(\frac{2.6.10+6.10.14+...+194+198+202}{1.3.5+3.5.7+...+97.99.101}\)\(=\frac{2.2.2\left(1.3.5\right)+2.2.2\left(3.5.7\right)+...+2.2.2\left(97.99.101\right)}{1.3.5+3.5.7+...+97.99.101}\)
\(=\frac{2.2.2\left(1.3.5+3.5.7+...+97.99.101\right)}{1.3.5+3.5.7+...+97.99.101}\)\(=\frac{2.2.2}{1}=8\)
17 - 16 + 15 + 14 - 13 + 12 - 11 - 10 + 9 - 8 + 7 - 6 - 5
= (17 - 16) + (15 - 10 - 5) + (14 - 13) + (12 - 11) + (9 - 8) + (7 + 6)
= 1 + 0 + 1 + 1 + 1 + 13
= 1 + 1 + 1 + 1 + 13
= (1 + 1 + 1 + 1) + 13
= 1 x 4 + 13
= 4 + 13
= 17
= 5
a, 70 - 5 : ( x - 3 ) = 4
=> 5 : ( x - 3 ) = 66
=> x - 3 = \(\frac{5}{66}\)
=> x = \(\frac{203}{66}\)
b, => 10 + 2x = 16
=> 2x = 6
=> x = 3
c, => 12x - 33 = \(\frac{1}{3}\)
=> 12x = \(\frac{100}{3}\)
=> x = \(\frac{25}{9}\)
d, => [ ( 2x + 14 ) : 2 ^ 2 - 3 ] : 2 = 1
=> ( 2x + 14 ) : 2^2 -3 = 2
=> ( 2x + 14 ) : 4 = 5
=> 2x + 14 = 20
=> 2x = 6
=> x = 3
=-5-[5+(-4)]
=5-1
=4
( 14 - 12 - 7 ) - [ - ( -3 + 2 ) + ( 5 - 9 ) ]
= ( 2 - 7 ) - [ 1 + ( - 4 ) ]
= - 5 - ( - 5 )
= - 5 +5
= 0