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A = \(\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{12}\)
A = \(\left(-\frac{1}{4}\right)+\frac{5}{6}-\frac{7}{12}\)
A = \(\frac{7}{12}-\frac{7}{12}\)
A = \(0\).
Mình làm câu A thôi nhé.
Chúc bạn học tốt!
a: \(=\left(\dfrac{-4}{10}+\dfrac{3}{10}\right):\left(\dfrac{-2}{5}+\dfrac{10}{3}\right)\)
\(=\dfrac{-1}{10}:\dfrac{-6+50}{15}=\dfrac{-1}{10}\cdot\dfrac{15}{44}=\dfrac{-3}{88}\)
b: \(=\left|\dfrac{-4+9}{6}\right|\cdot\left(-\dfrac{4}{5}-\dfrac{5}{2}\right)\)
\(=\dfrac{5}{6}\cdot\dfrac{-33}{10}=\dfrac{-1}{2}\cdot\dfrac{11}{2}=-\dfrac{11}{4}\)
c: \(=\left(\dfrac{12}{35}-\dfrac{6}{7}+\dfrac{9}{7}\right)\cdot\dfrac{-7}{6}+\dfrac{7}{5}\)
\(=\left(\dfrac{12}{35}+\dfrac{3}{7}\right)\cdot\dfrac{-7}{6}+\dfrac{7}{5}\)
\(=\dfrac{12+15}{35}\cdot\dfrac{-7}{6}+\dfrac{7}{5}\)
\(=\dfrac{27}{35}\cdot\dfrac{-7}{6}+\dfrac{7}{5}=\dfrac{1}{2}\)
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)