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a: \(=\dfrac{3\cdot\left(6+4\right)}{6\cdot2}=\dfrac{3\cdot10}{6\cdot2}=\dfrac{30}{12}=\dfrac{5}{2}\)
b: \(=\dfrac{12\left(6-1\right)}{3\left(4+5\right)}=4\cdot\dfrac{5}{9}=\dfrac{20}{9}\)
\(\frac{15}{a}\cdot\frac{2}{3}\cdot\frac{3}{2}=\frac{5}{4}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{4}:\frac{3}{2}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{4}\cdot\frac{2}{3}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{10}{12}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{6}\)
\(\frac{15}{a}=\frac{5}{6}:\frac{2}{3}\)
\(\frac{15}{a}=\frac{5}{6}\cdot\frac{3}{2}\)
\(\frac{15}{a}=\frac{15}{12}\)
Ta có: \(\frac{15}{a}=\frac{15}{12}\)
Mặt khác: 15 = 15 => a = 12
Vậy a tìm được bằng 12
4/5 x 3/4 - 3/10
= 12/20 - 3/10
= 12/20 - 6/20
= 6/20
= 3/10
\(\frac{4}{5}\cdot\frac{3}{7}+\frac{4}{5}\cdot\frac{6}{7}-\frac{4}{5}\cdot\frac{4}{14}\)
\(=\frac{4}{5}\cdot\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{14}\right)\)
\(=\frac{4}{5}\cdot1=\frac{4}{5}\)
#Louis
\(\dfrac{5}{3}\times x-\dfrac{2}{3}=\dfrac{1}{5}\\ \Leftrightarrow\dfrac{5}{3}x=\dfrac{1}{5}+\dfrac{2}{3}\\ \Leftrightarrow\dfrac{5}{3}x=\dfrac{3+10}{15}\\ \Leftrightarrow\dfrac{5}{3}x=\dfrac{13}{15}\\ \Rightarrow x=\dfrac{13}{15}:\dfrac{5}{3}=\dfrac{13}{25}\)