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a)\(m_{Na}=11\cdot\left(1,6726\cdot10^{-27}+9,1094\cdot10^{-31}\right)+12\cdot1,6748\cdot10^{-27}=18,3986\cdot10^{-27}+100,2034\cdot10^{-31}+20,0976\cdot10^{-27}=\left(183986+100,2034+200976\right)\cdot10^{-31}=385062,2034\cdot10^{-31}\sim38,5\cdot10^{-27}kg\sim23,193u\)Các phần khác tương tự.
\(m_{ntu}=m_p+m_n+m_e\)
mp = 8. 1,6726.10-27 kg = 13,3808.10-27kg
me = 8.9,1094.10-31kg = 72,876.10-31kg.
mn = 8. 1,6748.10-27 kg = 13,3984.10-27kg
mhn = mp + mn = 26,7792.10-27kg.
mngt= mhn + me = 26,7865.10-27kg.
Bài 2:
\(a.Z=P=E=7\\ A=Z+N=7+7=14\left(đ.v.C\right)\\ \Rightarrow KH:^{14}_7N\\ b.Z=P=E=14\\ A=Z+N=14+16=30\left(đ.v.C\right)\\ \Rightarrow KH:^{30}_{14}Si\\ c.Z=P=E=8\\ A=Z+N=8+10=18\left(đ.v.C\right)\\ \Rightarrow KH:^{18}_8O\\ Nguyên.tử.X:\\ Z=P=E=A-N=27-14=13\\ \Rightarrow KH:^{27}_{13}Al\\ d.A=20\left(đ.v.C\right);P=N=\dfrac{A}{2}=\dfrac{20}{2}=10\\ \Rightarrow KH:^{20}_{10}Ne\\ e.Z^+=13^+\Rightarrow Z=13\\ A=Z+N=13+14=27\left(đ.v.C\right)\\ \Rightarrow KH:^{27}_{13}Al\)
\(f.\\ \left\{{}\begin{matrix}P=E\\A=P+N=35\\S=P+N+E=52\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2P+N=52\\P+N=35\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}P=E=Z=17\\N=18\end{matrix}\right.\\ \Rightarrow A=Z+N=17+18=35\left(đ.v.C\right)\\ \Rightarrow KH:^{35}_{17}Cl\)
a, Khoi luong cua 1 nguyen tu F la :
mF= 9me + 9mp +9mn =9.0,00055+9.1+9.1 =18,00495u
b, tthe tich cua hat nhan la :
V=\(\frac{4}{3}\)πr\(^{^{ }3}\)=\(\frac{4}{3}\).3,14.\(\frac{10^{-14}}{2}\)=2,1.10\(^{-14}\) m\(^3\)
khoi luong rieng cua hat nhan ngtu F la :
D=\(\frac{1800495.1,6605.10^{-27}}{2,1.10^{-14}}\) kg/m\(^3\)
c,lam tuong tu nha
Đáp án D