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=\((11.3^{29}-\left(3^2\right)^{15}):(2^2.3^{28})\)
=\((11.3^{29}-3^{30}):(2^2.3^{28})\)
=\((11.3^{29}-(3^{29}.3):(2^2.3^{28})\)
=\(\frac{3^{29}.(11-3)}{3^{28}.4}\)
=\(\frac{3.8}{4}\)=\(\frac{3.2}{1}\)=6
\(\frac{11.3^{22}.3^7-\left(3^2\right)^{15}}{2^2.3^{28}}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}=\frac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)
\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{22}.3^7-\left(3^2\right)^{15}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{22}.3^7-3^{30}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{29}-3^{30}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}\)
\(=\frac{11.3^{29}-3.3^{29}}{4.3^{28}}\)
\(=\frac{\left(11-3\right).3^{29}}{4.3^{28}}\)
\(=\frac{8.3^{29}}{4.3^{28}}\)
\(=2.3=6\)
\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}=\frac{3.8}{4}=3.2=6\)