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\(92-\left(2\cdot x+4\right)\cdot9=15\cdot2+6\)
\(92-\left(2x+4\right)\cdot9=36\)
\(\left(2x+4\right)\cdot9=92-36\)
\(\left(2x+4\right)\cdot9=56\)
\(2x+4=\frac{56}{9}\)
\(2x=\frac{56}{9}-4\)
\(2x=\frac{20}{9}\)
\(x=\frac{10}{9}\)
`a)4/5+5 1/2 xx (4,5-2)+7/10`
`=4/5+11/2*2,5+7/10`
`=0,8+2,2+0,7`
`=3+0,7=3,7`
`b)125%xx 17/4:(1 5/16-0,5)+2008`
`=1,25xx4,25:13/16+2008`
`=85/13+2008`
`=2014 7/13`
`c)5/11+(16/11+1)`
`=5/11+1+5/11+1`
`=2+10/11=32/11`
`d)3/17+11/4+5/8+14/17+3/8`
`=3/17+14/17+5/8+3/8+11/4`
`=1+1+11/4`
`=19/4`
a)
\(\dfrac{4}{5}+5\dfrac{1}{2}x\left(4,5-2\right)=\dfrac{7}{10}\)
<=> \(\dfrac{11}{2}x\times2,5=\dfrac{7}{10}-\dfrac{4}{5}=\dfrac{-1}{10}\)
<=> \(\dfrac{55}{4}x=\dfrac{-1}{10}< =>x=\dfrac{-2}{275}\)
b) \(125\%\times\dfrac{17}{4}:\left(1\dfrac{5}{16}-0,5\right)+2008\)
= \(\dfrac{85}{16}:\left(\dfrac{21}{16}-\dfrac{1}{2}\right)+2008=\dfrac{85}{16}:\dfrac{13}{16}+2008=\dfrac{26189}{13}\)
c) \(\dfrac{5}{11}+\left(\dfrac{16}{11}+1\right)\)
= \(\dfrac{21}{11}+1=\dfrac{32}{11}\)
d) \(\left(\dfrac{3}{17}+\dfrac{14}{17}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{11}{4}\)
= 1 + 1 + \(\dfrac{11}{4}\) = \(\dfrac{19}{4}\)
[ ( x + 32 ) - 17 ] . 2 = 42
[ ( x + 32 ) - 17 ] = 42 : 2
[ ( x + 32 ) - 17 ] = 21
( x + 32 ) = 21 + 17
x + 32 = 38
x = 38 - 32
x = 6
Vậy x = 6
((x + 32) - 17 .2 = 42
<=> ( x + 32) - 17 = 42 : 2
<=> (x + 32) - 17 = 21
<=> x + 32 = 17 + 21
<=> x + 32 = 38
<=> x = 38 - 32
<=> x = 6