Question

[nguyen thi khanh hoa]

\(\int\limits^{\frac{\Pi}{3}}_{\frac{\Pi}{4}}\frac{1}{sin^2xcos^2x}dx\)

Answer 1

[ngo mai trang]

\(\int\limits^{ }_{ }\frac{cos^2x+sin^2x}{sin^2xcos^2x}dx=\int\limits\frac{1}{sin^2x}dx+\int\limits^{ }_{ }\frac{1}{cos^2x}dx=tanx+cotgx\)

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