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\(b,81^{13}:3^{35}.\)
\(=\left(3^4\right)^{13}:\left(3^1\right)^{35}.\)
\(=3^{52}:3^{35}.\)
\(=3^{52-35}=3^{17}.\)
Vậy.....
\(c,128^{18}:32^{23}.\)
\(=\left(2^7\right)^{18}:\left(2^5\right)^{23}.\)
\(=2^{126}:2^{115}.\)
\(=2^{126-115}.\)
\(=2^{11}=2048.\)
Vậy.....
~ Hok tốt!!! ~ =))
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Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1.Tính
a) (-16).10=-160
b) 23.(-5)=-115
c) (-24).(-25)=600
d) (-12)^2=144
2.Tính
a) 2316+115=2431
b) (-315)+(-15)=-330
c) (-215)+125=-90
d) (-200)+200=0
3.Hảy tính
a) (-457)+(-123)+23+237=-320
b) (-135)+48+140+(-5)=48
chúc bạn là bài tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 27 + ( -2019 ) + ( -27 )
= [ 27 + ( - 27) ] + ( - 2019)
= 0 - 2019
= - 2019
b) ( -10 ) + 23 + ( -20 ) + 30
= [ ( - 10 ) + (- 20) + 30]+ 23
= [ ( - 30) + 30] + 23
= 0 + 23 = 23
c) ( -2 ).125.( -5 ).( -8 ).( +17 )
= [ - 2 . ( - 5 )] . [ 125 . ( - 8)] . 17
= 10 . 1000 . 17
= 170000
d) ( -9 ) + ( -15 ) + ( -33 )
= - 24 + ( - 33 )
= - 57
e) ( -15 ).6 = - 80
f) 5.( -9 ) + 4.9 = 9 . ( - 5 + 4) = 9 . 1 = 9
![](https://rs.olm.vn/images/avt/0.png?1311)
1.
-16+23+x=-16
<=>7+x=-16
<=>x=-16-7
<=>x=-23
Vậy...
2.
2x – 35 = 15
<=>2x=50
<=>x=25
Vậy...
3.
3x + 17 = 12
<=>3x=-5
<=>x=-5/3
Vậy...
4.
│x - 1│= 0
<=>x-1=0
<=>x=1
Vậy..
5.
-13 .│x│ = -26
<=>IxI=2
<=>x=-2 và x=2
Vậy..
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: 2763+152
=2915
b) Ta có: (-7)+(-14)
=-(7+14)
=-21
e) Ta có: (-35)+(-9)
=-(35+9)
=-44
g) Ta có: (-5)+(-248)
=-(5+248)
=-253
k) Ta có: (-23)+105
=105-23
=82
Bài làm
| 23 + ( -18 ) | - | -5 | + ( 20190 )
= | 5 | - 5 + 1
= 5 - 5 + 1
= 1
# Chúc bạn học tốt #
Bài làm
| 23 + ( -18 ) | - | 5 | + ( -20190 )
= | 5 | - | 5 | + ( -1 )
= 5 - 5 + ( -1 )
= 0 + ( -1 )
= -1
# Chúc bạn học tốt #