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c: \(=3.7\cdot12+3.7\cdot70+3.7\cdot18\)
=3,7(12+70+18)
=3,7*100=370
d: \(=202,2\left(3+6+1\right)=202,2\cdot10=2022\)
e: \(=4,5\cdot15+4,5\cdot90+4,5\cdot25=4,5\left(15+90+25\right)=585\)
i: \(=3.18\cdot4+3.18\cdot75+3.1\cdot8+3.18\cdot13\)
\(=3,18\left(4+75+13\right)+24,8\)
\(=317.36\)
\(\dfrac{2x-3}{4}.\dfrac{6}{5}=\dfrac{21}{10}\\ \Leftrightarrow\dfrac{2x-3}{4}=\dfrac{7}{4}\\ \Leftrightarrow2x-3=7\\ \Leftrightarrow2x=10\\ \Leftrightarrow x=5\)
\(=\dfrac{9}{4}\cdot\dfrac{-2}{7}+\dfrac{9}{4}\cdot\dfrac{9}{7}=\dfrac{9}{4}\left(-\dfrac{2}{7}+\dfrac{9}{7}\right)=\dfrac{9}{4}\)
c) C = 129 - 5 . [29 - (6 - 1)2]
C = 129 - 5 . (29 - 52)
C = 129 - 5 . (29 - 25)
C = 129 - 5 . 4
C = 129 - 20
C = 109
7: Ta có: \(25\cdot\left(-\dfrac{1}{5}\right)^3-2\cdot\left(-\dfrac{1}{2}\right)^2+\dfrac{2}{5}-\dfrac{1}{2}\)
\(=25\cdot\dfrac{-1}{125}-2\cdot\dfrac{1}{4}+\dfrac{2}{5}-\dfrac{1}{2}\)
\(=\dfrac{-1}{5}+\dfrac{2}{5}-\dfrac{1}{2}-\dfrac{1}{2}\)
\(=\dfrac{1}{5}-1=-\dfrac{4}{5}\)