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`@` `\text {Ans}`
`\downarrow`
`(x - 3,5) \div 1 1/2 - 2,5 = -1 3/4`
`=> (x-3,5) \div 1 1/2 = -1 3/4 + 2,5`
`=> (x-3,5) \div 1 1/2 = 3/4`
`=> x - 3,5 = 3/4 * 1 1/2`
`=> x - 3,5 = 9/8`
`=> x = 9/8 + 3,5`
`=> x = 37/8`
Vậy, `x = 37/8.`
Lời giải:
Bổ sung điều kiện $x$ nguyên.
Ta có:
$2x+7\vdots x-2$
$\Rightarrow 2(x-2)+11\vdots x-2$
$\Rightarrow 11\vdots x-2$
$\Rightarrow x-2\in \left\{1; -1; 11; -11\right\}$
$\Rightarrow x\in \left\{3; 1; 13; -9\right\}$
a) \(1\frac{2}{7} = 1 + \frac{2}{7} = \frac{9}{2}\)
\(\begin{array}{l}x:1\frac{2}{7} = - 3,5\\x:\frac{9}{7} = - \frac{7}{2}\\x = - \frac{7}{2}.\frac{9}{7}\\x = - \frac{9}{2}\end{array}\)
b) \(0,4.x - \frac{1}{5}.x = \frac{3}{4}\)
\(\begin{array}{l}\frac{2}{5}.x - \frac{1}{5}.x = \frac{3}{4}\\\left( {\frac{2}{5} - \frac{1}{5}} \right).x = \frac{3}{4}\\\frac{1}{5}.x = \frac{3}{4}\\x = \frac{3}{4}:\frac{1}{5}\\x = \frac{3}{4}.5\\x = \frac{{15}}{4}\end{array}\)
a) \(x=-\dfrac{3}{5}\times\dfrac{9}{7}=-\dfrac{27}{35}\)
b) \(x\left(0,4-\dfrac{1}{5}\right)=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)
a, \(x=-3,5.\dfrac{9}{7}=-\dfrac{9}{2}\)
b, \(\dfrac{2}{5}x-\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow\dfrac{1}{5}x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}:\dfrac{1}{5}=\dfrac{15}{4}\)
2:
a: =>x=1/2+1/6=3/6+1/6=4/6=2/3
b: =>x+3,5=7,8-6,3=1,5
=>x=1,5-3,5=-2
c: =>(35-x)/-105=1/5
=>35-x=-21
=>x=56
1
c hình như tính bình thường thôi:v
d
= 1,75 : 5 + 2,5 . (16 – 4 . 4,1)
= 1,75 : 5 + 2,5 . (16 – 16,4)
= 1,75 : 5 + 2,5 . (−0,4)
= 0,35 − 1
= −0,65.
2
a
\(\Rightarrow x=\dfrac{1}{2}+\dfrac{1}{6}=\dfrac{3}{6}+\dfrac{1}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
b
\(\Rightarrow x+\dfrac{35}{10}=\dfrac{78}{10}-\dfrac{63}{5}:2\\ \Rightarrow x+\dfrac{35}{10}=\dfrac{78}{10}-\dfrac{63}{10}=\dfrac{15}{10}\\ \Rightarrow x=\dfrac{15}{10}-\dfrac{35}{10}=-2\)
c không rõ đề:v
\(\left|-x-\frac{2}{5}\right|+\frac{1}{2}=3,5\)
\(\left|-x-\frac{2}{5}\right|=3,5-0,5\)
\(\left|-x-\frac{2}{5}\right|=3\)
\(\Rightarrow\orbr{\begin{cases}-x-\frac{2}{5}=3\\-x-\frac{2}{5}=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}-x=\frac{17}{5}\\-x=-\frac{13}{5}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=-\frac{17}{5}\\x=\frac{13}{5}\end{cases}}}\)
Vậy \(x=-\frac{17}{5}\)hoặc \(x=\frac{13}{5}\)
Mày không biết trả lời mình mẫu giáo mà
:-P :-P :-P :-( B-) :-\ B-) O:-)
\(\left|x-3,5\right|=\dfrac{4}{7}\)
=>\(\left[{}\begin{matrix}x-\dfrac{7}{2}=\dfrac{4}{7}\\x-\dfrac{7}{2}=-\dfrac{4}{7}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{7}+\dfrac{7}{2}=\dfrac{8}{14}+\dfrac{49}{14}=\dfrac{57}{14}\\x=-\dfrac{4}{7}+\dfrac{7}{2}=\dfrac{-8}{14}+\dfrac{49}{18}=\dfrac{41}{14}\end{matrix}\right.\)