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a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)
Bài 1 :
Ta có : 120 = 6 x 20
120 = 3 x 2 x 4 x 5
Vậy số đó là : 3245
Bài 2 :
A =\(\left(\frac{28}{31}:\frac{8}{9}\right):\left(\frac{7}{31}:\frac{2}{9}\right)\)
A = \(\left(\frac{28}{31}X\frac{9}{8}\right):\left(\frac{7}{31}X\frac{9}{2}\right)\)
A = \(\left(\frac{28X9}{31X8}\right):\left(\frac{7X9}{31X2}\right)\)
A =\(\frac{28X9}{31X8}X\frac{31X2}{7X9}\)
A = \(\frac{28X9X31X2}{31X8X7X9}\)
A = \(\frac{28X2}{8X7}\)
A = \(\frac{7X4X2}{4X2X7}\)
A = 1
Bài 1: số đó là: 456
Bài 2:
A = \(\left(\frac{28}{31}:\frac{8}{9}\right):\left(\frac{7}{31}:\frac{2}{9}\right)\)
\(=\left(\frac{28}{31}.\frac{9}{8}\right):\left(\frac{7}{31}.\frac{9}{2}\right)\)
\(=\frac{63}{62}:\frac{63}{62}=1\)
VẬy: A = 1
Chú ý: Dấu \(.\)là dấu nhân.
\(\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}=\frac{31}{1.3}+\frac{31}{3.5}+\frac{31}{5.7}+\frac{31}{7.9}+\frac{31}{9.11}+\frac{31}{11.13}\\ \)
\(=\frac{31}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right)\)
\(=\frac{31}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)
\(=\frac{31}{2}.\left(1-\frac{1}{13}\right)=\frac{31}{2}.\frac{12}{13}=\frac{31.6}{13}=\frac{186}{13}\)
\(\Rightarrow x-\frac{186}{13}=\frac{9}{13}\Leftrightarrow x=\frac{195}{13}=15\)
\(x-\left(\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}\right)=\)\(\frac{9}{13}\)(1)
Đặt \(A=\frac{31}{3}+\frac{31}{15}+\frac{31}{35}+\frac{31}{63}+\frac{31}{99}+\frac{31}{143}\)
\(A=31\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}\right)\)
\(\Rightarrow2A=31\left(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\right)\)
\(2A=31\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right)\)
\(2A=31\left(2-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)
\(2A=31\left(2-\frac{1}{13}\right)\)
\(2A=31.\frac{25}{13}\)
\(2A=\frac{775}{13}\)
\(\Rightarrow A=\frac{775}{13}:2\)
\(A=\frac{775}{26}\)
Thay vào (1) ta có:
\(x-\frac{775}{26}=\frac{9}{13}\)
\(\Leftrightarrow x=\frac{9}{13}+\frac{775}{26}\)
\(\Leftrightarrow x=\frac{61}{2}\)
a) = 34/31 - 3/31 - 19/28 = 1 - 19/28 = 9/28
b) 18/13 - 5/13 + 55/46 = 1 + 55/46 = 101/46
c) 7/3 - 4/3 + 11/5 = 1 + 11/5 = 16/5
d) ( 27/25 - 2/25 ) - ( 5/9 + 4/9 ) = 1 - 1 = 0
e) 2,125 + 43/8 + 7,15 + 137/20 + 7,5
= 2,125 + 5,375 + 7,15 + 6,85 + 7,5
= 7,5 + 14 + 7,5
= 7,5 + 7,5 + 14
= 15 + 14
= 29
a) Nhóm 34/31 với 3/31
b) Nhóm 18/13 với 5/13
c) Nhóm 7/3 với 4/3
d) Phá ngoặc ra rồi tính
e) Bêến đổi đều thành phân số rồi tính
\(2\frac{3}{13}\cdot5\frac{4}{5}\cdot7\frac{6}{7}:\frac{2}{8}=\frac{29}{13}\cdot\frac{29}{5}\cdot\frac{55}{7}:\frac{2}{8}=\frac{29\cdot29\cdot55\cdot8}{13\cdot5\cdot7\cdot2}=\frac{29\cdot29\cdot11\cdot4}{13\cdot1\cdot7\cdot1}=\frac{37004}{91}\)
Chúc bạn học tốt!^_^
\(\frac{12}{35}:\frac{35}{25}=\frac{12}{35}.\frac{25}{35}=\frac{12.25}{35.35}=\frac{12.5.5}{7.5.7.5}=\frac{12}{49}\)
\(\frac{9}{22}.\frac{33}{18}=\frac{9.33}{22.18}=\frac{9.3.11}{11.2.9.2}=\frac{3}{4}\)
\(=\frac{\frac{28}{31}.\frac{31}{7}}{\frac{8}{9}.\frac{9}{4}}=\frac{4}{2}=2\)