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c.\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\frac{25}{108}.\frac{5751}{25}+\frac{187}{4}}{\frac{100}{21}:-\frac{41}{21}}\)
\(\frac{\frac{213}{4}+\frac{187}{4}}{-\frac{100}{41}}\)
\(\frac{100}{-\frac{100}{41}}=-41\)
a. \(\frac{4}{9}:-\frac{1}{7}+6\frac{5}{9}:-\frac{1}{7}\)
\(\left(\frac{4}{9}+6\frac{5}{9}\right):-\frac{1}{7}\)
\(7:-\frac{1}{7}=-49\)
\(\frac{1}{2}-\frac{2}{3}+\frac{3}{4}-\frac{4}{5}+\frac{5}{6}-\frac{6}{7}+\frac{4}{5}-\frac{3}{4}+\frac{2}{3}-\frac{1}{2}\)
= \(\left(\frac{1}{2}-\frac{1}{2}\right)+\left(\frac{-2}{3}+\frac{2}{3}\right)+\left(\frac{3}{4}-\frac{3}{4}\right)+\left(\frac{-4}{5}+\frac{4}{5}\right)+\frac{5}{6}-\frac{6}{7}\)
= \(\frac{5}{6}-\frac{6}{7}\)
= \(\frac{-1}{42}\)
\(\frac{1}{2}-\frac{2}{3}+\frac{3}{4}-\frac{4}{5}+\frac{5}{6}-\frac{6}{5}+\frac{4}{5}-\frac{3}{4}+\frac{2}{3}-\frac{1}{2}\)
\(=\left(\frac{1}{2}-\frac{1}{2}\right)+\left(\frac{-2}{3}+\frac{2}{3}\right)+\left(\frac{3}{4}-\frac{3}{4}\right)+\left(\frac{-4}{5}+\frac{4}{5}\right)+\frac{5}{6}-\frac{6}{7}\)
\(=\frac{5}{6}-\frac{6}{7}\)
\(=\frac{-1}{42}\)
Ta có \(\frac{6}{7}:\left(\frac{1}{3}-\frac{-5}{2}\right)^2\)
\(=\frac{6}{7}:\left(\frac{1}{3}+\frac{5}{2}\right)^2\)
\(=\frac{6}{7}:\left(\frac{17}{3}\right)^2\)
\(=\frac{6}{7}:\frac{289}{9}\)
\(=\frac{54}{2023}\)