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\(\frac{3-\frac{3}{7}+\frac{3}{13}-\frac{3}{2018}}{7-\frac{7}{20}+\frac{7}{13}-\frac{7}{2018}}\)
\(=\frac{3\left(1-\frac{1}{20}+\frac{1}{13}-\frac{1}{2018}\right)}{7\left(1-\frac{1}{20}+\frac{1}{13}-\frac{1}{2018}\right)}\)
\(=\frac{3}{7}\)
\(x\cdot\frac{3+\frac{3}{20}+\frac{3}{13}+\frac{3}{2013}}{5+\frac{5}{20}+\frac{5}{13}+\frac{5}{2013}}=\frac{5}{3}\)
\(x\cdot\frac{3\cdot\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}{5\cdot\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}=\frac{5}{3}\)
\(x\cdot\frac{3}{5}=\frac{5}{3}\)
\(x=\frac{5}{3}:\frac{3}{5}\)
\(x=\frac{25}{9}\)
\(x.\frac{3+\frac{3}{20}+\frac{3}{13}+\frac{3}{2013}}{5+\frac{5}{20}+\frac{5}{13}+\frac{5}{2013}}=\frac{5}{3}\)
\(x.\frac{3.\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}{5.\left(1+\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}=\frac{5}{3}\)
\(x.\frac{3}{5}=\frac{5}{3}\)
\(x=\frac{5}{3}:\frac{3}{5}\)
\(x=\frac{25}{9}\)
\(x.\frac{\frac{3}{20}+\frac{3}{13}+\frac{3}{2013}}{\frac{5}{20}+\frac{5}{13}+\frac{5}{2013}}=\frac{5}{3}\)
\(\Rightarrow x.\frac{3\left(\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}{5\left(\frac{1}{20}+\frac{1}{13}+\frac{1}{2013}\right)}=\frac{5}{3}\)
\(\Rightarrow x.\frac{3}{5}=\frac{5}{3}\)
\(\Rightarrow x=\frac{5}{3}:\frac{3}{5}=\frac{25}{9}\)
vậy \(x=\frac{25}{9}\)
\(\Rightarrow x.\frac{3\left(\frac{1}{10}+\frac{1}{13}+\frac{1}{2012}\right)}{5\left(\frac{1}{10}+\frac{1}{13}+\frac{1}{2012}\right)}=\frac{5}{3}\)
\(\Rightarrow x.\frac{3}{5}=\frac{5}{3}\)
\(\Rightarrow x=\frac{25}{9}\)