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\(\frac{27^6.81^8.3^9}{3^7.3^6.3^{15}}=\frac{\left(3^3\right)^6.\left(3^4\right)^8.3^9}{3^7.3^6.3^{15}}=\frac{3^{18}.3^{32}.3^9}{3^7.3^6.3^{15}}\)
= \(\frac{3^{59}}{3^{28}}=3^{59}:3^{28}=3^{31}\)
Bài làm:
Ta có: \(\frac{9^2.\left(-4\right)^5.72}{5.\left(-6\right)^6}\cdot\frac{6^3.81.\left(-4\right)}{\left(-8\right)^6.3^9}\)
\(=\frac{3^2.-2^{10}.2^3.3^2.2^3.3^3.3^4.-2^2}{5.2^3.3^3.2^{18}.3^9}\)
\(=\frac{2^{18}.3^{11}}{2^{21}.3^{12}.5}\)
\(=\frac{1}{2^3.2.5}=\frac{1}{120}\)
\(\frac{25^5.2^{10}}{20^4.5^4}\)
=\(\frac{25^5.2^{10}}{20^4.25^2}\)
=\(\frac{25^3.2^{10}}{20^4}\)
=\(\frac{25^3.1024}{160000}\)
=\(\frac{25^3.4}{25^2}\)
=\(25.4\)
=100
\(M=\frac{9^4.27^5.3^6.3^4}{3^8.81^4.243.8^2}\)
\(M=\frac{\left(3^2\right)^4.\left(3^3\right)^5.3^6.3^4}{3^8.\left(3^4\right)^4.\left(3^5\right).\left(2^3\right)}\)
\(M=\frac{3^8.3^{15}.3^6.3^4}{3^8.3^{16}.3^5.8}\)
\(M=\frac{3^{33}}{3^{29}.8}\)
\(M=\frac{3^4}{1.8}\)
\(M=\frac{81}{8}\)
Chúc bạn học tốt !!!
gọi A = 224.39.62=224.39.22.32=226.311
B = 22.121115 - 166.312 = 22.222.311.3.5 - 248.312 = 244.312.5 - 248.312 = (244.312)(5 - 24)
=>\(\frac{A}{B}\)= \(\frac{2^{26}.3^{11}}{\left(2^{44}.3^{12}\right)\left(5-2^4\right)}\)= \(\frac{1.\left(2^{26}.3^{11}\right)}{\left(2^{18}.3\right).\left(2^{26}.3^{11}\right).\left(-11\right)}\)= \(\frac{1}{\left(2^{18}.3\right).\left(-11\right)}\)
nhớ k cho mik nha
\(m=\dfrac{2^7\cdot3^5+2^4\cdot3^9}{2^6\cdot3^5+2^3\cdot3^9}\)
\(m=\dfrac{2^4\cdot3^5\cdot\left(2^3+3^4\right)}{2^3\cdot3^5\cdot\left(2^3+3^4\right)}\)
\(m=\dfrac{2^4\cdot3^5}{2^3\cdot3^5}\)
\(m=\dfrac{2^4}{2^3}\)
\(m=2^{4-3}\)
\(m=2\)
Câu 1 xem kỉ đề
\(B,\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5-2.49^5}=\frac{7^{12}.5-7^{11}}{7^{10}.5-2.7^{10}}=\frac{7^{11}.\left(7.5-1\right)}{7^{10}.\left(5-2\right)}=\frac{7.34}{3}=\frac{238}{3}\)
a) A=212.35-\(\frac{2^{12}.3^6}{2^{12}}\)+93+84.35
=212.35-36+36+212.35
=213.35
b)B=496.5-5.\(\frac{7^{11}}{\left(-7\right)^{10}}-2.49^5\)
=496.5-7.5-2.495
=712.5-7.5-2.710
Lời giải:
\(M=\frac{9^4.27^5.3^6.3^4}{3^8.81^4.234.8^2}=\frac{(3^2)^4.(3^3)^5.3^6.3^4}{3^8.(3^4)^4.2.3^2.13.(2^3)^2}\)
\(=\frac{3^8.3^{15}.3^6.3^4}{3^8.3^{16}.2.3^2.13.2^6}=\frac{3^{33}}{3^{26}.2^7.13}=\frac{3^7}{2^7.13}\)
\(\frac{2^{15}.2+3}{8^6.3^9}=\frac{2^{16}+3}{2^{18}.3.3^8}=\frac{2^{16}+3}{2^{16}.2^2.3.3^8}=\frac{1}{2^2.3^8}\)