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Đặt A=1.2.3+2.3.4+3.4.5+4.5.6+...+98.99.100
4A=(1.2.3+2.3.4+3.4.5+4.5.6+...+98.99.100)4
4A=1.2.3(4-0)+2.3.4(5-1)+3.4.5(6-2)+4.5.6(7-3)+...+98.99.100(101-97)
4A=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+4.5.6.7-3.4.5.6+...+98.99.100.101-97.98.99.100
4A=1.2.3.4-1.2.3.4+2.3.4.5-2.3.4.5+3.4.5.6-3.4.5.6+...+97.98.99.100-97.98.99.100+98.99.100.101
4A=98.99.100.101
=>A=98.99.100.101/4
D = 1.2.3 + 2.3.4+3.4.5+...+30.31.32
=> 4D = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + .... + 30.31.32.4
=> 4D = 1.2.3.4 + 2.3.4.(5 - 1) + 3.4.5.(6 - 2) + ... + 30.31.32.(33 - 29)
=> 4D = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 + ... + 30.31.32.33 - 29.30.31.32
=> 4D = 30.31.32.33
=> D = \(\frac{30\cdot31\cdot32\cdot33}{4}=245520\)
4N = 1.2.3.4+ 2.3.4.4 + .... + 19.20.21.4
4N = 1.2.3.(4-0) + ...+ 19.20.21.(22-18)
4N = 1.2.3.4 - 0.1.2.3 + .... + 19.20.21.22-18.19.20.21
4N = 19.20.21.22
N = 19.5.21.22
Lời giải:
\(2A=\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+....+\frac{38-36}{36.37.38}+.\frac{39-37}{37.38.39}\)
\(=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{36.37}-\frac{1}{37.38}+\frac{1}{37.38}-\frac{1}{38.39}\)
\(=\frac{1}{1.2}-\frac{1}{38.39}=\frac{370}{741}\)
đặt A = 1.2.3 + 2.3.4 + 3.4.5 + ... + 48.49.50
4A = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + ...+ 48.49.50.4
4A = 1.2.3.4 + 2.3.4.(5-1) + 3.4.5.(6-2) + ... + 48.49.50.(51-47)
4A = 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 + ... + 48.49.50.51 - 47.48.49.50
4A = 48.49.50.51
A = \(\frac{48.49.50.51}{4}\)
A = 1499400
Ta có:
B=1.2.3+2.3.4+3.4.5+...+20.21.22
=>4B=1.2.3(4-0)+2.3.4(5-1)+3.4.5(6-2)+...+20.21.22(23-19)
<=>4B=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+...+20.21.22.23-19.20.21.22
<=>4B=20.21.22.23
<=>B=5.21.22.23=53130
\(B=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+..+\frac{1}{7.8.9}+\frac{1}{8.9.10}\)
\(B=2\times\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+..+\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)
\(B=2\times\left(1-\frac{1}{10}\right)\)
\(B=2\times\frac{9}{10}\)
\(B=\frac{9}{5}\)
\(B=2\times\left(\frac{1}{1\times2}-\frac{1}{2\times3}+\frac{1}{2\times3}-\frac{1}{3\times4}+\frac{1}{3\times4}-\frac{1}{4\times5}+..+\frac{1}{9\times10}\right)\)
\(B=2\times\left(\frac{1}{1\times2}-\frac{1}{9\times10}\right)\)
\(B=2\times\frac{22}{45}\)
\(B=\frac{44}{45}\)
4E = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 + ... + 40.41.42.4
4E = 1.2.3.4 + 2.3.4.( 5 - 1 ) + 3.4.5.( 6 - 2 ) + .. + 40.41.42.( 43 - 39 )
4E = 1.2.3.4 + 2.3.4.5 - 1.2.3.4.+ 3.4.5.6 - 2.3.4.5 + .. + 40.41.42.43 - 39.40.41.42
4E = 40.41.42.43
E = 10 . 41 . 42 . 43 = 740640
4E = 1. 2 . 3 .4 + 2 . 3 . 4. 4 + 3. 4 . 5. 4 + ...+40 . 41. 42 . 4
4E = 1 . 2. 3. 4 + 2 . 3 . 4. 5 - 2. 3 .4 + 3 . 4. 5 . 6 - 3 . 4. 5 . 2 + ...+ 40 . 41. 42 . 43 - 40 . 41. 42 . 39
4E = 40 . 41. 42. 43
E = (40 . 41. 42. 43) : 4
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