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2006 . 125 + \(\dfrac{1000}{126}\) . 2005 - 888 = 265774,6984
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\(\dfrac{2006.125+1000}{126.2006-1006}\)
\(=\)\(\dfrac{2006.125+1000}{(125+1).2006-1006}\)
\(=\)\(\dfrac{2006.125+1000}{125.2006+1.2006-1006}\)
\(=\)\(\dfrac{2006.125+1000}{125.2006+2006-1006}\)
\(=\)\(\dfrac{2006.125+1000}{125.2006+1000}\)
\(=\) 1
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2006 x 125 + 1000/126 x 2006 - 1006
= 2006 . 125 + 1000/125 . 2006 + 1 .2006 - 1006
= 2006 . 125 + 100/125 . 2006 + 1000
= 1
2006 x 125 + 1000/126 x 2006 - 1006
= 2006 x 125 + 1000/125 x 2006 + 1 x 2006 - 1006
= 2006 x 125 + 1000/125 x 2006 + 1000
= 1
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a)A=3\(\dfrac{1}{11}\) x \(\dfrac{27}{46}\) x 1\(\dfrac{6}{17}\) x 2\(\dfrac{4}{9}\)
A=\(\dfrac{34}{11}\) x \(\dfrac{27}{46}\) x \(\dfrac{23}{17}\) x \(\dfrac{22}{9}\)
A=\(\dfrac{34\times27\times23\times22}{11\times46\times17\times9}\)
A=\(\dfrac{2\times3}{1}\)
A=6
mk cảm ơn bạn nhìu nha . bk có thể giải cho mk câu B đc ko
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\(\frac{2004.2005+2006.6-6}{2005.197+4.2005}\)= \(\frac{2004.2005+\left(2006-1\right).6}{2005.\left(197+4\right)}\)= \(\frac{2004.2005+2005.6}{2005.201}\)= \(\frac{\left(2004+6\right).2005}{2005.201}\)
= \(\frac{2010}{201}\)= \(10\)
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\(\frac{2016x125+1000}{126x2005-888}\)
\(=\frac{2005x125+(125x11+1000)}{125x2005+(2005-888)}\)
\(=\frac{2005x125+2375}{125x2005+1117}\)
\(=\frac{2005x125+1117+1258}{125x2005+1117}\)
\(=1+\frac{1258}{125x2005+1117}\)
xem lại đề giúp mk nha!
Ta có :
Tử số :
( 2005 + 1 ) . 125 + 1000
2005 . 125 + 125 + 1000
2005 . 125 +1125
Mẫu Số :
( 125 + 1 ) . 2005 - 888
125 . 2005 + 2005 - 888
125 . 2005 + 1117
Ta có phân số : \(\dfrac{2005\cdot125+1125}{125\cdot2005+1117}\) = \(\dfrac{1125}{1117}\)