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\(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}\)
=\(\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(5.7+9\right)}\)
= \(\frac{8}{35+9}\)
= \(\frac{8}{44}\)
= \(\frac{2}{11}\)
\(\frac{5^{11}\cdot7^{12}+5^{11}\cdot7^{11}}{5^{12}\cdot7^{11}+9\cdot5^{11}\cdot7^{11}}\)
=\(\frac{5^{11}\cdot\left(7^{12}+7^{11}\right)}{5^{11}\left(5\cdot7^{11}+9\cdot7^{11}\right)}\)
=\(\frac{7^{12}+7^{11}}{5\cdot7^{11}+9\cdot7^{11}}\)
=\(\frac{7^{11}\left(7+1\right)}{7^{11}\left(5+9\right)}\)
=\(\frac{8}{14}=\frac{4}{7}\)
Kết quả này chắc chắn là đúng đấy
a)\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{-5}{9}\)
b)\(\frac{\left(-11\right)^5.13^7}{11^5.13^8}=-\frac{1}{13}\)
c)\(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9\left(3-1\right)}{2^9.3^{10}}=2\)
d(\(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(35+9\right)}=\frac{1}{6}\)
\(\frac{5^{11}.7^{12}.5^{11}.7^{11}}{5^{12}.7^{12}.9.5^{11}.7^{11}}\)=\(\frac{1}{45}\)
Mình quên viết số 1 ở phần 7^1. nó là 7^11 nhé
\(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{11}+9.5^{11}.7^{11}}\)
\(=\frac{5^{11}.7^{11}.7^1+5^{11}.7^{11}}{5^{11}.5^1.7^{11}+3^2.5^{11}.7^{11}}\)
\(=\frac{5^{11}.\left(7^{11}+7^{11}\right).7^1}{5^{11}.\left(7^{11}+7^{11}\right).5^1.3^2}\)
\(=\frac{7}{5.3^2}\)
\(=\frac{7}{45}\)