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55-54+53=53.(52-51+50)=53.(25-5+1)=53.21=53.3.7 chia hết cho 7
=>ĐPCM
76+75-74=74.(72+71-70)=74.(49+7-1)=74.55=74.5.11 chia hết cho 11
=>ĐPCM
\(S=2\left(1+2\right)+2^3\left(1+2\right)+...+2^{11}\left(1+2\right)=3\left(2+2^3+...+2^{11}\right)⋮3\)
\(S=2\left(1+2+2^2\right)+...+2^{10}\left(1+2+2^2\right)=7\left(2+...+2^{10}\right)⋮7\)
Vì S chia hết cho 2 và S chia hết cho 3
nên \(S⋮6\)
\(\overline{aaa}+\overline{bbb}=111.a+111.b=111\left(a+b\right)=37\times3\times\left(a+b\right)⋮37\)
\(3.\overline{abcabc}-605=3.\left(1000\overline{abc}+\overline{abc}\right)-605=3.1001.\overline{abc}-695=11\left(273\overline{abc}-55\right)⋮11\)
\(\overline{abc}+\overline{bca}+\overline{cab}=\left(100a+10b+c\right)+\left(100b+10c+a\right)+\left(100c+10a+b\right)\)
\(=111\left(a+b+c\right)=37\times3\times\left(a+b+c\right)⋮37\)
1)Đưa về lũy thừa cùng cơ số 2
82= \(\left(2^3\right)^2=2^6\) 323= \(\left(2^5\right)^3=2^{15}\) 644= \(\left(2^6\right)^4=2^{24}\) 43= \(\left(2^2\right)^{^3}=2^6\)
2)Đưa về lũy thừa cùng cơ số 3
93= \(\left(3^2\right)^3=3^6\) 274= \(\left(3^3\right)^4=3^{12}\) 95= \(\left(3^2\right)^5=3^{10}\) 816= \(\left(3^4\right)^6=3^{24}\)
3)Đưa về lũy thừa cùng cơ số 2
83:42= \(\left(2^3\right)^3:\left(2^2\right)^2=2^9:2^4=2^5\) 162:32= \(\left(2^4\right)^2:2^5=2^8:2^5=2^3\)
\(64^4:4^3=\left(2^6\right)^4:\left(2^2\right)^3=2^{24}:2^6=2^{18}\) 323:82= \(\left(2^5\right)^3:\left(2^3\right)^2=2^{15}:2^6=2^9\)
a: \(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\dfrac{-7}{11}=-\dfrac{5}{11}\)
b: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\left(4+\dfrac{3}{8}\right)\)
\(=\dfrac{12}{7}\cdot\dfrac{35}{8}=\dfrac{3}{2}\cdot5=\dfrac{15}{2}\)
c: \(=\dfrac{2}{15}-\dfrac{2}{15}\cdot5+\dfrac{3}{15}=\dfrac{2}{15}\cdot\left(-4\right)+\dfrac{3}{15}=\dfrac{-8+3}{15}=\dfrac{-5}{15}=-\dfrac{1}{3}\)
d: \(=\dfrac{4}{9}\left(19+\dfrac{1}{3}-39-\dfrac{1}{3}\right)=\dfrac{4}{9}\cdot\left(-20\right)=-\dfrac{80}{9}\)
1) 55 - 54 + 53 = 53 . 52 - 53 . 5 - 53
= 53 . ( 52 - 5 + 1 )
= 53 . ( 25 - 5 - 1 )
= 53 . 21
= 53 . 3 . 7 chia hết cho 7
Vậy chứng minh 55 - 54 + 53 chia hết cho7
2) 76 + 75 - 74 = 74 . 72 + 74 . 7 - 74
= 74 . ( 72 + 7 - 1 )
= 74 . ( 49 + 7 - 1 )
= 74 . 55
= 74 . 5 .11 chia hết cho 11
Vậy chứng minh 76 + 75 - 74 chia hết cho 11
Tích mình nha !!!!!!!!!!!!!!!!!