Bài 6: Đặt tính rồi tính:
575 + 418 | 464 + 618 | 958 - 461 | 825 - 619 |
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Bài 7: Tìm X, biết:
a) X – 231 = 948 – 539 | b) 502 – X = 107 x 3 |
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Bài 8: Một hinh chữ nhật có chu vi 96m, chiêu dài hơn chiều rộng 8m. Tính chiêu dài và chiều rộng hinh chữ nhật?
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Bài 7: Tìm X, biết:
a) X – 231 = 948 – 539
b) 502 – X = 107 x 3
.........\(x-231=499\\ \Rightarrow x=499+231\\ \Rightarrow x=730\).............................
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...........\(502-x=321\\ \Rightarrow x=502-231\\ \Rightarrow x=271\).
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Bài 8: Một hinh chữ nhật có chu vi 96m, chiêu dài hơn chiều rộng 8m. Tính chiêu dài và chiều rộng hinh chữ nhật?
Nửa chu vi là : \(96:2=48\left(m\right)\)
Chiều rộng là : \(\dfrac{48-8}{2}=20\left(m\right)\)
Chiều dài là : 48-20=28(m)
575+418=993
464+618=1082
958-461=497
825-619=206