Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 17 :
1) ab + ac = a ( b + c )
2) ab - ac + ad = a ( b - c + d )
3) ax - bx - cx + dx = x ( a- b - c + d )
4) a(b + c) – d(b + c) = ( b + c ) ( a - d )
5) ac – ad + bc – bd = a( c - d ) + b ( c - d ) = ( c- d ) ( a + b )
6) ax + by + bx + ay = a( x+ y ) + b ( x + y ) = ( x + y ) (a +b )
Bài 18:
1/ (a – b + c) – (a + c) = a - b + c - a - c = -b
2/ (a + b) – (b – a) + c = a + b - b + a + c = 2a + 2
3/ - (a + b – c) + (a – b – c) = -a -b + c + a - b - c = -2b
4/ a(b + c) – a(b + d) = a ( b + c - b - d ) = a( c - d )
5/ a(b – c) + a(d + c) = a ( b - c + d + c ) = a ( b+ d )
1.
1) a ( b + c )
2) a ( b-c+d)
3) x ( a-b-c+d)
4) ( b+c ) (a - d )
5) a (c-d) + b (c-d) =(c-d) (a + b )
6) a ( x+y) + b ( y+x) = (x+y) ( a+b)
2.
1) a - b + c - a - c = -b
2) a + b - b + a + c = 2a + c
3) - a - b + c + a - b - c = -2b
4) ab + ac - ab - ad = ac-ad = a (c-d)
5) ab - ac + ad + ac = ab + ad = a (b+d)
\(a,\left(a-b+c\right)-\left(a+c\right)=-b\)
Ta có: \(VT=\left(a-b+c\right)-\left(a+c\right)=a-b+c-a-c=-b=VP\left(đpcm\right)\)
\(b,\left(a+b\right)-\left(b-a\right)+c=2a+c\)
Ta có: \(VT=\left(a+b\right)-\left(b-a\right)+c=a+b-b+a+c=2a+c=VP\left(đpcm\right)\)
\(c,-\left(a+b-c\right)+\left(a-b-c\right)=-2b\)
Ta có: \(VT=-\left(a+b-c\right)+\left(a-b-c\right)=-a-b+c+a-b-c=-2b=VP\left(đpcm\right)\)
\(d,a\left(b+c\right)-a\left(b+d\right)=a\left(c-d\right)\)
Ta có: \(VT=a\left(b+c\right)-a\left(b+d\right)=ab+ac-ab-ad=ac-ad=a\left(c-d\right)=VP\left(đpcm\right)\)
\(e,a\left(b-c\right)+a\left(d+c\right)=a\left(b+d\right)\)
Ta có: \(VT=a\left(b-c\right)+a\left(d+c\right)=ab-ac+ad+ac=ab+ad=a\left(b+d\right)=VP\left(đpcm\right)\)
Bài 1:
a, (a - b + c) - (a + c)
= a - b + c - a - c
= ( a - a ) + ( c- c ) - b
= -b
b, ( a + b ) - (b - a ) + c
= a + b - b + a + c
= ( a + a ) + ( b- b ) + c
= 2a + c
c, - ( a + b - c) + (a - b -c)
= -a -b + c + a - b - c
= ( -a + a ) - ( b + b ) + ( c - c)
= - 2b
d, a(b + c) - a ( b + d )
= ab + ac - ab - ad
= ac - ad
= a( c-d )
e, a( b - c ) + a( d + c )
= ab - ac + ad + ac
= ab + ad
= a( b+d )
Bài 2:
a, ab + ac = a( b + c)
b, ab - ac + ad= a( b -c + d )
c, ax - bx - cx + dx = x( a - b - c + d)
d, a(b + c ) - d( b + c) = ( b+c ).(a - d )
e, ac - ad + bc - bd = a ( c - d ) + b( c - d) = (a+b).( c - d )
g, ax + by + bx + ay = a( x + y) + b(y + x) = ( a+b).( x+y )
ĐẶT NHÂN TỬ CHUNG NHA!
1) ab - ac + ad = a( b- c +d )
2) ax - bx - cx + dx = x( a-b-c+d)
3) a.( b + c ) - d . ( b + c )= (b+c)(a-d)
4) ac - ad + bc - bd = a( c-d) + b( c-d) = (a+b)(c-d)
5) ax + by + bx + ay= a( x+y) + b( x+y) = (a+b)(x+y)
1) ab + ac = a(b + c)
2) ab - ac + ad = a(b - c + d)
3) ax - bx - cx + dx = x(a - b - c + d)
4) a(b + c) - d(b + c) = (b + c)(a - d)
5) ac - ad + bc - bd = a(c - d) + b(c - d) = (c - d)(a + b)
6) ax + by + bx + ay = (ax + ay) + (bx + by) = a(x + y) + b(x + y) = (x + y)(a + b)
ab + ac = a ( b + c )
ab - ac + ad = a ( b - c + d )
ax - bx - cx + dx = x ( a - b - c + d )
1/ab+ac=a(b+c)
2/ab-ac+ad=a(b-c)+ad=a(b-c+d)
3/ax-bx-cx+dx=x(a-b-c)+xd=x(a-b-c+d)
4/a(b+c)-d(b+c)=(ab+ac)-(bd+cd)=b(a+d)-c(a+d)=a+d(b+c)
5/ac-ad+bc-bd=a(c-d)+b(c-d)=c-d(a+b)
6/ax+by+bx+ay=a(x+y)+b(x+y)=x+y(a+b)
1?
a(b+c)
a(b-c+d)
x(a-b-c+d)
(b+c)(a-d)
(c-d)(a+b)
(x+-y)(a+b)
1/ ab+ ac
=a(b+c)
2/ ab - ac + ad
=a(b-c+d)
3/ ax - bx - cx + dx
=x(a-b-c+d)
4/ a(b + c) - d(b + c)
=(a-d)(b+c)
5/ ac - ad + bc - bd
=a(c-d)+b(c-d)
=(a+b)(c-d)
6/ ax + by + bx + ay
=x(a+b)+y(b+a)
=(x+y)(b+a)
A) ab + ac=a.(b+c)
B)ab - ac + ad=a.(b-c+d)
C) ã-bx-cx+dx=x.(a-b-c+d)
D)a(b+c) - d(b+c)=(b+c).(a-d)
E) ac-ad+bc-bd=a.(c-d)+b.(c-d)=(c-d).(a+b)
G) ax+by+bx+ay=x.(a+b)+y.(b+a)=(a+b).((x.y)
1, ab + ac = a(b+c)
2, ab - ac + ad = a(b-c+d)
3, ax-bx-cx+dx = x(a-b-c+d)
4, a(b+c) - d(b+c) = (a-d)(b+c)
5, ac-ad+bc-bd = a(c-d) + b(c-d) = (a+b)(c-d)
6, ax+by+bx+ay=ax+ay+bx+by=a(x+y)+b(x+y)=(a+b)(x+y)
a(b+c)
a(b-c+d)
x(a-b-c+d)
(b+c)(a-d)
a(c-d)+c(c-d)=(c-d)(a+c)
a(x+y)+b(x+y)=(x+y)(a+b)
T
1 a(b+c)
2 a(b-c+d)
3 x(a-b-c+d)
4 (b+c)(a-d)
5 a(c-d)+b(c-d)
(c-d)(a+b)
6 ax+by+bx+ay
ax+ay+bx+by
a(x+y)+b(x+y)
(x+y)(a+b)
làm được nhiu ây thui, mí bài kia tự làm nhak
hihhhi
bài 2 \
1 (a-b+c)-(a+c)=-b
phá ngoặc
=a-b+c-a-c
=-b
2 làm giống bài 1 í. phá ngoặc hớt, mí bài còn lại cũng lm tương tự
phá ngoặc là được thui :)))))