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Đặt A:
A = \(\frac{4,5:47,375-\left(26\frac{1}{3}-18.0,75\right).2,4:0,88}{17,81:1,37-23\frac{2}{3}:1\frac{5}{6}}\)
= \(\frac{\frac{9}{2}:\left[\frac{379}{8}-\left(\frac{79}{3}-\frac{27}{2}\right).\frac{30}{11}\right]}{13-\frac{71}{3}.\frac{6}{11}}\)
= \(\frac{\frac{9}{2}:\left[\frac{379}{8}-\frac{77}{6}.\frac{30}{11}\right]}{13-\frac{142}{11}}\)
= \(\frac{\frac{9}{2}:\left[\frac{379}{8}-35\right]}{\frac{1}{11}}\)
= \(\left(\frac{9}{2}:\frac{99}{8}\right).1\)
= \(\frac{4}{11}.11\) = 4
=> A = 4
\(\frac{4,5\div\left[47,735-\left(26\frac{1}{3}-18.0,75\right).2,4\div0,88\right]}{17,81\div1,37-23\frac{2}{3}\div1\frac{5}{6}}\)
\(=\frac{4,5\div\left[47,735-\left(\frac{79}{3}-\frac{27}{2}\right)\cdot\frac{30}{11}\right]}{13-\frac{142}{11}}\)
\(=\frac{4,5\div\left[47,735-\frac{77}{6}\cdot\frac{30}{11}\right]}{\frac{1}{11}}=\frac{4,5\div\left[47,735-35\right]}{\frac{1}{11}}\)
\(=\frac{4,5\div12,735}{\frac{1}{11}}=\frac{100}{283}\div\frac{1}{11}=\frac{1100}{283}\)
\(G=\dfrac{\dfrac{9}{2}:\left[\dfrac{379}{8}-\dfrac{77}{6}\cdot\dfrac{12}{5}:\dfrac{22}{25}\right]}{13-\dfrac{71}{3}:\dfrac{11}{6}}=\dfrac{\dfrac{9}{2}:\dfrac{99}{8}}{\dfrac{1}{11}}=\dfrac{4}{11}:\dfrac{1}{11}=4\)
mk làm được rồi G=4