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a 10=2.5
24=23.3
BCNN(10,24)=23.5.3=120
→BC(10,24)=B(120)={0;120;240;360;480;....}
b 20=22.5
35=7.5
60=22.3.5
BCNN(20,35,60)=22.3.5.7=420
→BC(20,35,60)=B(420)={0;420;840;1260;...}
c 48=24.3
120=23.3.5
BCNN(48,120)=24.3.5=240
→BC(48,120)=B(240)={0;240;480;720;...}
d
18=2.32
24=23.3
32=25
BCNN(18,24,32)=25.32=288
→BC(18,24,32)=B(288)={0;288;576;864;...}
18=2.32 36=22.32 72=23.32
UWCLN(18;36;72)=2.32=18
BCNN(18;36;72)=23.32=72
UWC(18;36;72)=UW(18)={1;2;3;6;9;18}
BC(18;36;72)=B(72)={0;72;144;216;288;...}
(x - 1)(y - 4) = 3
=> x - 1; y - 4 thuộc Ư(3)
=> x - 1; y - 4 thuộc {1; 3; -1; -3}
ta có bảng :
x-1 | -1 | 1 | -3 | 3 |
y-4 | -3 | 3 | -1 | 1 |
x | 0 | 2 | -2 | 4 |
y | 1 | 7 | 3 | 5 |
vậy_
\(\left(x-1\right)\left(x-4\right)=3\)
\(\Rightarrow x-1;y-4\inƯ\left(3\right)\)
Vì \(\in\)Ư (3)=\(\left\{\mp1;\mp3\right\}\)
Tìm xTa có
\(x-1=-1;x=-1+1=0\)
\(x-1=1;x=1+1=2\)
\(x-1=-3;x=-3+1=-2\)
\(x-1=3;x=3+1=4\)
Vậy .....
Tìm y Ta có :
\(y-4=-3;y=-3+4=1\)
\(y-4=3;y=3+4=7\)
\(y-4=-1;y=-1+4=3\)
\(y-4=1;y=1+4=5\)
Vì:\(7< a< 11\)
Nên:\(a=8\) hoặc \(a=9\)
\(\Rightarrow b=10\)
Vậy:\(a=8\) hoặc \(a=9;b=10\)
a,UCLN(220,240.300)=20;BCNN(220,240,300)=13200
B,UCLN(40,75,106)=1;B,BCNN(40,75,106)=31800
C,UCLN(18,36,72)=18;C,BCNN(18,36,72)=72
a)UCLN(220,240,300)=20; BCNN(220,2420,300)=13200
b)UCLN(40,75,106)=0; BCNN(40,75,106)=7950
c)UCLN(18,36,72)=18; BCNN(18,36,72)=72
`a, 18(x-16)=-36`
`=>x-16=-36:18`
`=>x-16=-2`
`=>x=-2+16`
`=>x= 14`
`b,(-12-x):(-5)=3`
`=>-12-x=3 . (-5)`
`=>-12-x=-15`
`=>x= -12-(-15)`
`=>x=-12+15`
`=>x= 3`
`c,11-(-53+x)=97`
`=>-53+x=11-97`
`=>-53+x=-86`
`=>x=-86-(-53)`
`=>x=-86+53`
`=>x= -33`
`d,-9.x+(-7).x=-48`
`=> [-9+(-7) ].x=-48`
`=>-16.x=-48`
`=>x=-48:(-16)`
`=>x= 3`
`e,(2x-1)^3=-27`
`=> (2x-1)^3=-3^3`
`=> 2x-1=-3`
`=>2x=-3+1`
`=>2x=-2`
`=>x=-2:2`
`=>x=-1`
bn tách ra nhé!
Bài 5 :
\(a,5x-16=40+x\)
\(\Leftrightarrow5x-x=40+16\)
\(\Leftrightarrow4x=56\)
\(\Leftrightarrow x=14\)
\(b,-41+2x-\left(-24\right)=4x-23-x\)
\(\Leftrightarrow-41+2x+24=4x-23-x\)
\(\Leftrightarrow2x-4x+x=41-24-23\)
\(\Leftrightarrow-x=-6\)
\(\Leftrightarrow x=6\)
\(c,2\left(x-5\right)-\left(x+6\right)=\left(-7\right)^2\)
\(\Leftrightarrow2x-10-x-6=49\)
\(\Leftrightarrow x=65\)
\(d,120-4\left(1-x\right)=106-3x\)
\(\Leftrightarrow120-4+4x=106-3x\)
\(\Leftrightarrow4x+3x=106-120+4\)
\(\Leftrightarrow7x=-10\)
\(\Leftrightarrow x=-\dfrac{10}{7}\)
\(BCNN\left(9,24,35\right)=2520\\ BCNN\left(18,36,108\right)=108\)
Cảm ơn nha :>