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Ta có: \(A=\dfrac{5\cdot\left(2^2\cdot3^2\right)^9\cdot\left(2^2\right)^6-2\cdot\left(2^2\cdot3\right)^{14}\cdot3^4}{5\cdot2^{28}\cdot3^{18}-7\cdot2^{29}\cdot3^{18}}\)
\(=\dfrac{5\cdot2^{18}\cdot3^{18}\cdot2^{12}-2\cdot2^{28}\cdot3^{14}\cdot3^4}{5\cdot2^{28}\cdot3^{18}-7\cdot2^{28}\cdot3^{18}\cdot2}\)
\(=\dfrac{5\cdot2^{30}\cdot3^{18}-2\cdot2^{28}\cdot3^{18}}{2^{28}\cdot3^{18}\cdot\left(5-7\cdot2\right)}\)
\(=\dfrac{2^{28}\cdot3^{18}\cdot\left(5\cdot2^2-2\right)}{2^{28}\cdot3^{18}\cdot\left(5-14\right)}\)
\(=\dfrac{20-2}{-9}=\dfrac{18}{-9}=-2\)
\(A=\frac{5.2^{18}.3^{18}.2^{12}-2.2^{28}.3^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(A=\frac{5.2^{30}.3^{18}-2^{29}.3^{18}}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(A=\frac{2^2\left(5.2^{28}.3^{18}\right)-2^{29}.3^{18}}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(A=\frac{2^2-1}{1-7}\)
\(A=\frac{3}{-6}=\frac{1}{-2}=-\frac{1}{2}\)
Ta có : N = \(\frac{5.\left(2^3.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^6}{5.^{28}.3^{19}-7.2^{29}.3^{18}}\)
= \(\frac{5.2^{18}.3^{18}.2^{12}-2.2^{28}.3^{14}.3^4}{2^{28}.3^{18}.\left(5-7.2\right)}\)
= \(\frac{5.2^{30}.3^{18}-2^{29}.3^{18}}{2^{28}.3^{18}.\left(-9\right)}\)
= \(\frac{3^{18}.2^{29}.\left(10-1\right)}{2^{28}.3^{18}.\left(-9\right)}=-2\)
Vậy N = -2
Kết quả dãy trên là 1678, hơi rắc rối tí, giải xong mà vã cả mồ hôi, cho mình ****>.<
52.3+22.{13+5[30:2.3-(33-30.2)]}
= 25.3+4.{13+5[45-(27-60)]}
= 75+4.{13+5[45-(-33)]}
= 75+4.{13+5[45+33]}
= 75+4.{13+5.78}
= 75+4.{13+390}
= 75+4.403
= 75+1612
= 1687