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a: \(125\left(19-135\right)-135\left(19-125\right)\)
\(=125\cdot19-125\cdot135-135\cdot19+135\cdot125\)
\(=125\cdot19-135\cdot19\)
\(=19\left(125-135\right)=-10\cdot19=-190\)
b: \(\left(-125\right)\left(135-19\right)-135\left(19-135\right)\)
\(=-125\cdot135+125\cdot19-135\cdot19+135^2\)
\(=135^2-135\cdot125+125\cdot19-135\cdot19\)
\(=135\left(135-125\right)+19\left(125-135\right)\)
\(=135\cdot10-19\cdot10\)
\(=116\cdot10=1160\)
c: \(125\left(19-135\right)+135\left(125-19\right)\)
\(=125\cdot19-125\cdot135+135\cdot125-135\cdot19\)
\(=125\cdot19-135\cdot19\)
\(=19\left(125-135\right)=19\cdot\left(-10\right)=-190\)
d: \(146\left(46-259\right)+259\left(146-46\right)\)
\(=146\cdot46-146\cdot259+259\cdot146-259\cdot46\)
\(=146\cdot46-259\cdot46\)
\(=46\left(146-259\right)\)
\(=46\cdot\left(-113\right)=-5198\)
e: \(195\left(17-185\right)-185\left(17-185\right)\)
\(=195\cdot17-195\cdot185-185\cdot17+185^2\)
\(=\left(195\cdot17-185\cdot17\right)-\left(195\cdot185-185^2\right)\)
\(=17\left(195-185\right)-185\left(195-185\right)\)
\(=10\left(17-185\right)=-168\cdot10=-1680\)
g: \(\left(-146\right)\left(19-156\right)+156\left(19-146\right)\)
\(=-146\cdot19+146\cdot156+156\cdot19-156\cdot146\)
\(=156\cdot19-146\cdot19=19\left(156-146\right)=190\)
h: \(\left(-243\right)\left(25-763\right)+763\left(25-243\right)\)
\(=-243\cdot25+243\cdot763+763\cdot25-763\cdot243\)
\(=763\cdot25-243\cdot25\)
\(=25\left(763-243\right)=520\cdot25=13000\)
1. 15^x=225
<=>15^x=15^2
=>x=2
vậy....
2. x^3=27
<=>x^3=3^3
=>x=3
vậy......
3. 4.2^x-3=125
4.2^x=128
2^x=32
2^x=2^5
=>x=5
vậy.....
\(15^x=225\)
\(\Leftrightarrow15^x=15^2\)
\(\Leftrightarrow x=2\)
\(x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
\(4.2^x-3=125\)
\(\Leftrightarrow4.2^x=125+3\)
\(\Leftrightarrow4.2^x=128\)
\(\Leftrightarrow2^x=128:4\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
~ Hok tốt ~
ta có : Cn=1
\(\Leftrightarrow c^n=1^n\left(n\inℕ^∗\right)\)
\(\Rightarrow c=1\)
A= (2+22)+(23+24)+...+(259+260)
A=2.(1+2)+23.(1+2)+...+259.(1+2)
A=2.3+23.3+...+259.3
A=3.(2+23+...+259)
Vì 3 chia hết cho 3 => 3.(2+23+...+259) chia hết cho 3
=>A chia hết cho 3
A = 2 + 22 + 23 + 24 + ... + 260
=> A = ( 2 + 22 ) + ( 23 + 24 ) + ... + ( 259 + 260 )
=> A = 2( 1 + 2 ) + 22(1 + 2 ) + ... + 259( 1 + 2 )
=> A = 2 . 3 + 22 . 3 + ... + 259 . 3
=> A = ( 2 + 22 + 259 ) . 3 chia hết cho 3
Vậy A chia hết cho A
\(1-2b+c-3a=9\)
\(\Leftrightarrow1-2\left(-3\right)+\left(-7\right)-3a=9\)
\(\Leftrightarrow1+6-7-3a=9\)
\(\Leftrightarrow-3a=9\Rightarrow a=\frac{9}{-3}=-3\)
Với b=-3; c=-7 ta được
1 - 2b + c - 3a = 9
<=> 1 - 2.(-3) + (-7) - 3a = -9
<=> 1 + 6 - 7 - 3a = -9
<=> -3a = -9
<=> a = 3
a) 40 và 60
Ta có Ư(40)\(\in\){1;2;4;5;6;8;10;16;20}
Ư(60)\(\in\){1;2;3;4;5;6;10;12;15;20;30)
ƯC(40;60)\(\in\){1;2;3;4;5;6;10;20}
Trong đó,20 là ƯCLN.Vậy ƯCLN(40;60)\(\in\){20}
b)
\(\Rightarrow27-2\cdot5^{x-2}=5^2=25\\ \Rightarrow2\cdot5^{x-2}=2\\ \Rightarrow5^{x-2}=1=5^0\\ \Rightarrow x-2=0\\ \Rightarrow x=2\)
2