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[Toán 8] Rút gọn $ (3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)$ | HOCMAI Forum - Cộng đồng học sinh Việt Nam
\(3(2^2+1)(2^4+1)(2^8+1)(2^16 +1) \)
\( = (2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)\)
\( = (2^4-1)(2^4+1)(2^8+1)(2^16+1) \)
\( = (2^8-1)(2^8+1)(2^16+1) \)
\(= (2^16 -1)(2^16+1) = 2^32 - 1\)
3(2^2 +1) (2^4 +1 ) (2^8 +1) (2^16 +1)
= (4-1)(2^2+1)(2^4 +1)(2^8+1)(2^16+1)
= [(2^2-1)(2^2+1)] (2^4+1) (2^8+1)(2^16+1)
=(2^4 -1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
= (2^16-1)(2^16+1)
= 2^23 -1
Chúc bạn học tốt
a) \(\left(x+2\right)\left(x-2\right)-\left(x-3\right)\left(x+1\right)\)
\(=x^2-4-\left(x^2+x-3x-3\right)\)
\(=x^2-4-x^2-x+3x+3\)
\(=2x-1\)
b) \(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(2^{16}-1\right)\left(2^{16}+1\right)=2^{32}-1\)
2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1
2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)
=(2^8-1)(2^8+1)(2^16+1)
=(2^16-1)(2^16+1)
=2^32-1
chúc bn hok tốt @_@
Rút gọn đa thức sau:
\(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
mk ko ghi lại đề
= (4-1)(.......
=(2^2-1)(2^2+1)(.....
=(2^4-1)(2^4+1)(......
=....
=2^32-1
\(3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(=\left(x^4-1\right)\left(x^4+1\right)\left(x^8+1\right)\left(x^{16}+1\right)\)
\(=\left(x^8-1\right)\left(x^8+1\right)\left(x^{16}+1\right)\)
\(=\left(x^{16}-1\right)\left(x^{16}+1\right)\)
\(=x^{32}-1\)