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Bạn lấy 1/5 ở cả phân số 1 và 2 làm thừa số chung sau đó rút gọn và sẽ tìm đc kết qyar là 0
\(P=2018.\left(\frac{\frac{1}{3}-\frac{1}{5}+\frac{1}{7}}{\frac{5}{3}-1+\frac{5}{7}}+\frac{1+\frac{4}{5}-\frac{2}{3}}{\frac{5}{4}+1-\frac{5}{6}}\right):\frac{20182018}{20192019}\)
\(P=\frac{\frac{1}{3}-\frac{1}{5}+\frac{1}{7}}{\frac{5}{3}-1+\frac{5}{7}}+\frac{1+\frac{4}{5}-\frac{2}{3}}{\frac{5}{4}+1-\frac{5}{6}}:\frac{20182018}{20192019}\)
\(P=\frac{\frac{1}{3}+\frac{1}{7}-\frac{1}{5}}{\frac{5}{3}+\frac{5}{7}-1}+\frac{1+\frac{4}{5}-\frac{2}{3}}{1+\frac{5}{4}-\frac{5}{6}}:\frac{20182018}{20192019}\)
\(P=20192019\left(\frac{1+\frac{4}{5}-\frac{2}{3}}{1+\frac{5}{4}-\frac{5}{6}}+\frac{\frac{1}{3}+\frac{1}{7}-\frac{1}{5}}{\frac{5}{3}+\frac{5}{7}-1}\right):20182018\)
\(P=2019\left(\frac{1+\frac{4}{5}-\frac{2}{3}}{1+\frac{5}{4}-\frac{5}{6}}+\frac{\frac{1}{3}+\frac{1}{7}-\frac{1}{5}}{\frac{5}{3}+\frac{5}{7}-1}\right).2018\)
\(P=2019\left(\frac{1}{5}+\frac{4}{5}\right):2018\)
\(P=2019.1:2018\)
\(P=\frac{2019}{2018}\)
\(P=2018.\frac{2019}{2018}\)
\(P=2019\)
a) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
= \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+\frac{1}{2}-\frac{36}{41}\)
= \(\frac{1}{2}-\left\{\frac{11}{24}+\frac{13}{24}\right\}-\left\{\frac{5}{41}+\frac{36}{41}\right\}\)
=\(\frac{1}{2}-\frac{24}{24}-\frac{41}{41}\)
=\(\frac{1}{2}-1-1\)
=\(\frac{-3}{2}\)
b) \(-12:\left\{\frac{3}{4}-\frac{5}{6}\right\}^2\)
= \(-12:\left\{\frac{9}{12}-\frac{10}{12}\right\}^2\)
= \(-12:\left\{\frac{-1}{12}\right\}^2\)
= \(-12:\frac{1}{144}\)
= \(-12.144\)
= -1728
c) \(\frac{7}{23}.\left[\left(\frac{-8}{6}\right)-\frac{45}{18}\right]\)
= \(\frac{7}{23}.\left[\left(\frac{-24}{18}\right)-\frac{45}{18}\right]\)
= \(\frac{7}{23}.\left(\frac{-23}{6}\right)\)
= \(\frac{-7}{6}\)
d) \(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
= \(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}.\frac{7}{5}\)
= \(\left\{23\frac{1}{4}-13\frac{1}{4}\right\}.\frac{7}{5}\)
= \(10.\frac{7}{5}\)
= 14
e) (1+23−14).(0,8−34)2
= (1+23−14).(\(\frac{4}{5}\)−34)2
= \(\left(\frac{12}{12}+\frac{8}{12}-\frac{3}{12}\right).\left(\frac{16}{20}-\frac{15}{20}\right)^2\)
= \(\frac{17}{12}.\left(\frac{1}{20}\right)^2\)
= \(\frac{17}{20}.\frac{1}{400}\)
= \(\frac{17}{8000}\)
đề sai ko bn nếu là \(\frac{5}{5^{2018}}\)thì sao ko viết bằng \(\frac{1}{5^{2017}}\)hay đề là \(\frac{1}{5^{2018}}\)
nếu đề đúng thì ns mik làm hộ cho còn nếu đề sai nhớ nói