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a: \(575-\left(2x+70\right)=445\)
=>\(2x+70=575-445=130\)
=>\(2x=130-70=60\)
=>x=60/2=30
b: \(575-2\left(x+70\right)=445\)
=>\(2\left(x+70\right)=575-445=130\)
=>x+70=130/2=65
=>x=65-70=-5
c: \(x^5=32\)
=>\(x^5=2^5\)
=>x=2
d: \(\left(3x-1\right)^3=8\)
=>\(\left(3x-1\right)^3=2^3\)
=>3x-1=2
=>3x=3
=>\(x=\dfrac{3}{3}=1\)
e: \(\left(x-2\right)^3=27\)
=>\(\left(x-2\right)^3=3^3\)
=>x-2=3
=>x=5
f: \(\left(2x-3\right)^2=9\)
=>\(\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
g: \(2x+5=3^4:3^2\)
=>\(2x+5=3^2\)
=>2x+5=9
=>2x=9-5=4
=>x=4/2=2
h: \(\left(4x-5^2\right)\cdot7^3=7^4\)
=>\(4x-25=\dfrac{7^4}{7^3}=7\)
=>4x=25+7=32
=>\(x=\dfrac{32}{4}=8\)
a) \(2x-49=5.3^2\)
\(\Leftrightarrow2x-49=45\)
\(\Leftrightarrow2x=94\)
\(\Leftrightarrow x=47\)
b) \(574-\left(6x+75\right)=445\)
\(\Leftrightarrow6x+75=129\)
\(\Leftrightarrow6x=53\Leftrightarrow x=\frac{53}{6}\)
c) \(\left|x-3\right|=2\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=2\\x-3=-2\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\x=1\end{cases}}}\)
\(a,4^{333}=\left(4^3\right)^{111}=64^{111}< 81^{111}=\left(3^4\right)^{111}=3^{444}< 3^{445}\\ b,39^{15}>36^{15}=\left(6^2\right)^{15}=6^{30}\\ c,25^{45}=\left(5^2\right)^{45}=5^{90}< 5^{102}=\left(5^3\right)^{34}=125^{34}\)
\(\text{30.(x+2)-6.(x+5)-24x=100}\)
\(30x+60-6x-30-24x=100\)
\(30x-6x-24x=100+30-60\)
\(0=70\\ \Rightarrow x\in\varnothing\)
\(\text{-12.(x-15)+7.(3-x)=15}\)
\(-12x+180+21-7x=15\)
\(-12x-7x=15-21-180\)
\(-19x=-186\)
\(x=\frac{186}{19}\)
\(\text{-(574+x)=(x-12-741)-23}\)
\(-574-x=x-12-741-23\)
\(-x-x=-752+574\)
\(-2x=-178\)
\(x=89\)
chúc bạn học tốt !!!
1) Sửa : D = 2100 - 299 - 298 - ... - 22 - 2 - 1
= 2100 - ( 299 + 298 + ... + 22 + 2 +1)
Đặt () = B
Ta có : 2B = 2100 + 299 + 298 + ...+ 22 + 2
2B - B = (2100 + 299 + 298 + ...+ 22 + 2) - ( 299 + 298 + ... + 22 + 2 +1)
B = 2100 - 1
=> D = 2100 - (2100 - 1)
= 2100 - 2100 + 1 ( mở dấu ngoặc)
= 1
Ta có S=1/2^2+1/3^2+1/4^2+...+1/9^2
<1/2²+1/2*3+1/3*4+....+1/8*9
=1/2²+1/2-1/3+1/3-1/4+....+1/8-1/9
=1/4+1/2-1/9=23/36<32/36=8/9 (♪)
Ta lại có S=1/2^2+1/3^2+1/4^2+...+1/9^2
>1/2²+1/3*4+1/4*5+....+1/9*10
=1/2²+1/3-1/4+1/4-1/5+........+1/9-1/10
=1/2²+1/3-1/10
=19/20>8/20=2/5 ( ♫)
Từ (♪)( ♫) cho ta đpcm
yêu cầu đề bài
a) \(574-\left(6.x+75\right)=445\)
\(\Rightarrow\left(6.x+75\right)=574-445\)
\(\Rightarrow\left(6.x+75\right)=129\)
\(\Rightarrow6.x=129-75\)
\(\Rightarrow6.x=54\)
\(\Rightarrow x=9\)
b) \(\left|x-3\right|=2\)
Vậy có 2 TH
TH1 : \(x-3=2\)
\(\Rightarrow x=2+3\)
\(\Rightarrow x=5\)
TH2 : \(x-3=-2\)
\(\Rightarrow x=-2+3\)
\(\Rightarrow x=1\)
Hc tốt