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2,
Q=\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)x\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
= \(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)x\left(\frac{3+\left(-2\right)+\left(-1\right)}{6}\right)\)
=\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)x0\)
Vậy Q=0
a) x + \(\frac{1}{6}\)=\(-\frac{3}{8}\)
x=\(\frac{-3}{8}-\frac{1}{6}\)
x=\(\frac{-13}{24}\)
b)\(\frac{1}{2}\)x + \(\frac{1}{8}\)x = \(\frac{3}{4}\)
\(\left(\frac{1}{2}+\frac{1}{8}\right)\)x = \(\frac{3}{4}\)
\(\frac{5}{8}\)x = \(\frac{3}{4}\)
x = \(\frac{3}{4}:\frac{5}{8}\)
x =\(\frac{6}{5}\)
c) 2 - l3/4-xl=7/12
l3/4-xl=17/12
nếu 3/4 - x > 0
thì 3/4 - x = 17/12
x= -2/3
nếu 3/4 - x <0
thì 3/4 - x = -17/12
x = 13/6
d) \(\left(2x-4.5\right):\frac{3}{4}-\frac{1}{3}=1\)
\(\left(2x-4.5\right):\frac{3}{4}=\frac{4}{3}\)
\(2x-4.5=1\)
2x = 5.5
x = 2.75
a, x + 1/6 = -3/8
x = -3/8 - 1/6
x = -13/24
b, 1/2x + 1/8x = 3/4
x * (1/2+1/8) = 3/4
x * 5/8 = 3/4
x = 3/4 : 5/8
x = 6/5
c, 2 - |3/4-x| = 7/12
|3/4-x| = 2 - 7/12
|3/4-x| = 17/12
=> 3/4 - x = 17/12 hoặc -17/12
# 3/4 - x = 17/12
=> x = -2/3
# 3/4 - x = -17/12
=> x = 13/6
=> x = { -2/3 ; 13/6}
d, (2x - 4,5) : 3/4 -1/3 = 1
(2x - 4,5) : 3/4 = 1 + 1/3
(2x - 4,5 ) : 3/4 = 4/3
2x - 4,5 = 4/3 * 3/4
2x - 4,5 = 1
2x = 1 + 4,5
2x = 5,5
x = 5,5 : 2
x = 2,75
-x-20-(8-2x)=(-12-3)
-x-20-8+2x=-15
x-28=-15
x=13
Vậy x=13
Intelligent help voi! Lam on di ma minh dang can gap lam!
a) (3^x-15)^7=0
=) 3x-15=0
=) 3x=15
=) x=5
b) 4^2.x-6=1
4^2.x-6= 4^0 ( vì số nào mũ không cũng bằng 1)
2x-6=0
2x=6
x=3
\(5+x-3=5-\left(x+4\right)\)
\(5+x-3=5-x-4\)
\(x+x=5-4-5+3\)
\(2x=-1\)
\(x=\frac{-1}{2}\)
vay \(x=\frac{-1}{2}\)
\(x-\left(5.\left|-7\right|+3\right)=\left|-8\right|+6-2\)
\(x-\left(5.7+3\right)=8+6-2\)
\(x-38=12\)
\(x=12+38\)
\(x=50\)
vay \(x=50\)
\(\left|x-3\right|+7=0\)
\(\left|x-3\right|=-7\)( ko ton tai)
\(12-3\left|x-1\right|=6\)
\(3\left|x-1\right|=6\)
\(\left|x-1\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
vay \(\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
hu hu giúp mihf vs