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b) Quy luật: Số tiếp theo = Tổng 2 số liền trước
=> 1 + 4 + 5 + 9 + 14 + 23 + 37 + 60 + 97 = (1 + 4 + 5) + (23 + 23) + (97 + 97)
= 10 + 46 +194 = 250
1. 41/7 - x = 25/9
=> x = 41/7 - 25/9
=> x = 194/63
2. 3x = 12,8
=> x = 12,8 : 3
=> x = 64/15
3. 41/2 x = 5
=> x = 5: 41/2
=> x = 10/41
4. 3/4 x = 1
=> x = 1: 3/4
=> x = 3/4
5. 4/5 : x = 3
=> x = 4/5 : 3
=> x = 4/15
6. 12/x = 4
=> x = 12/4
=> x = 3
7. 4/7 : x = 4/7
=> x = 4/7 : 4/7
=> x = 1
8. 2x - 3/4 = 7/8
=> 2x = 7/8 + 3/4
=> 2x = 13/8
=> x = 13/8 : 2
=> x =13/16
Ruby Chan :))
1, \(4\frac{1}{7}-x=2\frac{5}{9}\)
\(\frac{4\times7+1}{7}-x=\frac{2\times9+5}{9}\)
\(\frac{29}{7}-x=\frac{23}{9}\)
\(x=\frac{29}{7}-\frac{23}{9}\)
\(x=\frac{261}{63}-\frac{161}{63}\)
\(x=\frac{100}{63}\)
2, \(3\times x=12,18\)
\(x=12,18\div3\)
\(x=4,06\)
3, \(4\frac{1}{2}\times x=5\)
\(\frac{4\times2+1}{2}\times x=5\)
\(\frac{9}{2}\times x=5\)
\(x=5\div\frac{9}{2}\)
\(x=\frac{5\times2}{9}=\frac{10}{9}\)
4, \(\frac{3}{4}\times x=1\)
\(x=1\div\frac{3}{4}\)
\(x=\frac{1\times4}{3}=\frac{4}{3}\)
5, \(\frac{4}{5}\div x=3\)
\(x=\frac{4}{5}\div3\)
\(x=\frac{4}{5\times3}=\frac{4}{15}\)
6,\(\frac{12}{x}=4\)
\(x=12\div4\)
\(x=3\)
7, \(\frac{4}{7}\div x=\frac{4}{7}\)
\(x=\frac{4}{7}\div\frac{4}{7}\)
\(x=1\)
8, \(2x-\frac{3}{4}=\frac{7}{8}\)
\(2x=\frac{7}{8}+\frac{3}{4}\)
\(2x=\frac{7}{8}+\frac{6}{8}\)
\(2x=\frac{13}{8}\)
\(x=\frac{13}{8}\div2\)
\(x=\frac{13}{8\times2}=\frac{13}{16}\)
\(a,x-5⋮x+2\)
\(\Rightarrow x+2-7⋮x+2\)
\(\Rightarrow x+2\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
x + 2 = 1=> x = -1
x + 2 = -1 => x = -3
.... tương tự nhé ~
\(2x+3⋮x-5\)
\(\Rightarrow2x-10+7⋮x-5\)
\(\Rightarrow2\left(x-5\right)+7⋮x-5\)
\(\Rightarrow x-5\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
x - 5 = 1 => x = 6
....
a) 2.(5 +3 .x) + x =31
10 + 6.x + x = 31
6x + x = 31-10
7x = 21
x = 21:7
x=3
Vậy x=3
b) ( 3x -7 ) +2 . (5-2x) + 5x = 19
3x - 7 + 10 - 4x + 5x = 19
3x - 4x + 5x = 19 + 7 - 10
4x = 16
x = 16:4
x = 4
Vậy x=4
\(a,2\left(5+3x\right)+x=31\)
\(10+6x+x=31\)
\(10+7x=31\)
\(7x=21\)
\(x=3\)
\(b,\left(3x-7\right)+2\left(5-2x\right)+5x=19\)
\(3x-7+10-4x+5x=19\)
\(4x+3=19\)
\(4x=16\)
\(x=4\)
= 2 x X - 2 x 5 + 4 = X + 7
= X - 10 + 4 = 7 ( bớt cả hai vế đi X )
= X - 10 = 7 - 4
= X - 10 = 3
= X = 3 + 10
= X = 13
2 x [\(x\) - 5] + 4 = \(x\) + 7
\(x\) - 10 + 4 = 7 (bớt cả hai vế đi \(x\) )
\(x\)- 10 = 7 - 4
\(x\) - 10 = 3
\(x\) = 3 + 10
\(x\) = 13
a)
\(\left(x-5\right)+5=x\\ x-5+5=x\\ x+0=x\\ x=x\left(luôn.đúng\right)\)
Vậy phương trình có nghiệm với mọi giá trị x
b)
\(\left(x-7\right)-2x=7\\ x-7-2x=7\\ x-7-2x-7=0\\ -14-x=0\\ x=-14-0=-14\)
Vậy `x=-14`
cảm ơn