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a)2,5:7,5=x:3/5
0,(3)=x:3/5
\(\Rightarrow\)x= 1/5
b)x:2,5=0,003;0,75
x:2,5=1/250
\(\Rightarrow\)x=1/100
a)
\(3\frac{4}{5}:40\frac{8}{15}=0,25:x\)
\(\Rightarrow\frac{19}{5}:\frac{608}{15}=\frac{1}{4}.x\)
\(\Rightarrow\frac{1}{4}.x=\frac{3}{32}\)
\(\Rightarrow x=\frac{3}{8}\)
Vậy x = 3 / 8
b) \(\frac{5}{6}:x=20:3\)
\(\Rightarrow\frac{5}{6x}=\frac{20}{3}\)
\(\Rightarrow120x=15\)
\(\Rightarrow x=\frac{1}{5}\)
Vậy x = 1 / 5
c)
\(x:2,5=0,003:0,75\)
\(\Rightarrow x.\frac{2}{5}=\frac{3}{1000}.\frac{4}{3}\)
\(\Rightarrow x.\frac{2}{5}=\frac{1}{250}\)
\(\Rightarrow x=\frac{1}{100}\)
d)
\(\frac{2}{3}:0,4=x:\frac{4}{5}\)
\(\Rightarrow\frac{2}{3}:\frac{2}{5}=\frac{5x}{4}\)
\(\Rightarrow\frac{5x}{4}=\frac{5}{3}\)
\(\Rightarrow15x=20\)
\(\Rightarrow x=\frac{4}{3}\)
Vậy x = 4 / 3
a) \(\dfrac{5}{6}:x=30:3\)
\(\Leftrightarrow\dfrac{5}{6}:x=10\)
\(\Leftrightarrow x=\dfrac{5}{6}:10\)
\(\Leftrightarrow x=\dfrac{1}{12}\)
Vậy .......
b) \(x:2,5=0,003:0,75\)
\(\Leftrightarrow x:2,5=0,004\)
\(\Leftrightarrow x=0,004.2,5\)
\(\Leftrightarrow x=0,01\)
Vậy .......
c) \(3,8:\left(2x\right)=\dfrac{1}{4}:2\dfrac{2}{3}\)
\(\Leftrightarrow3,8:\left(2x\right)=\dfrac{1}{4}:\dfrac{8}{3}=\dfrac{3}{32}\)
\(\Leftrightarrow2x=3,8:\dfrac{3}{32}\)
\(\Leftrightarrow2x=\dfrac{698}{25}\)
\(\Leftrightarrow x=\dfrac{304}{15}\)
Vậy ...
d) \(\dfrac{2}{3}:0,4=x:\dfrac{4}{5}\)
\(\Leftrightarrow x:\dfrac{4}{5}=\dfrac{2}{3}\)
\(\Leftrightarrow x=\dfrac{8}{15}\)
Vậy ....
e) \(3\dfrac{4}{5}:40\dfrac{8}{15}=0,25:x\)
\(\Leftrightarrow0,25:x=\dfrac{19}{5}:\dfrac{608}{15}\)
\(\Leftrightarrow0,25x=\dfrac{57}{608}\)
\(\Leftrightarrow x=\dfrac{228}{608}\)
Vậy ...
e) \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
\(\Leftrightarrow xx=\left(-60\right)\left(-15\right)\)
\(\Leftrightarrow x^2=900\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2=30^2\\x^2=\left(-30\right)^2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=30\\x=-30\end{matrix}\right.\)
Vậy ...
0,01 : 2,5 = ( 0,75 . x ) : ( 0,75)
0,004 = ( 0,75 . x ) : ( 0,75)
( 0,75 . x ) = 0,004 x 0,75
( 0,75 . x ) = 0,003
x = 0,003 : 0,75
x = 0,004
a)\(\frac{x}{64}=-\frac{16}{x}\Rightarrow x^2=-16\cdot64\)
\(\Rightarrow x^2=-1024\)
Do \(x^2\ge0>-1024=VP\)
=>x vô nghiệm
b)0,01: 2,5= (0,75x) : 0,75
=>0,004=0,75:0,75*x
=>0,004=x
Vậy x=0,004
0,01 : 2,5 = (0,75x) : 0,75
⇔ (0,75x).2,5 = 0,01.0,75
⇔ (0,75x) = (0,01.0,75) : 2,5
⇔ 0,75x = 0,003
⇔ x = 0,003 : 0,75 ⇔ x = 0,004
a, \(\left|x\right|+0,75=2\Rightarrow\left|x\right|=1,25\Rightarrow x=\pm1,25\)
b, \(\left|x+\dfrac{1}{3}\right|-4=1\Rightarrow\left|x+\dfrac{1}{3}\right|=5\Rightarrow\left|x\right|=\dfrac{14}{3}\Rightarrow x=\pm\dfrac{14}{3}\)
c,
\(\left|x\right|+2,5=0\Rightarrow\left|x\right|=-0,25\) (vô lí)
Vì \(\left|x\right|\ge0\) => x vô nghiệm
a) \(\left|x\right|+0,75=2\)
\(\Leftrightarrow\left|x\right|=2-0,75=1,25\)
\(\Rightarrow\left[{}\begin{matrix}x=-1,25\\x=1,25\end{matrix}\right.\)
b) \(\left|x+\dfrac{1}{3}\right|-4=1\)
\(\Leftrightarrow\left|x+\dfrac{1}{3}\right|=1+4=5\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=5\\x+\dfrac{1}{3}=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{14}{3}\\x=-\dfrac{16}{3}\end{matrix}\right.\)
c) \(\left|x\right|+2,5=0\)
\(\Leftrightarrow\left|x\right|=0-2,5=-2,5\)
Vì \(\left|x\right|\ge0\) mà \(-2,5< 0\) nên \(x\in\varnothing\)
x:2,5=0,003:0,75
=>x:2,5= 0,004
=>x=0,004.2,5
=>x= 0,01
Vậy x=0,01