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a) = 53+4+1 = 58
b) = 65-4 = 6
c) = 32+3+4-7 = 32
d) = x4+2+1 = x7
e) = 812+10+3 = 825
1. \(5^3.5^4.5=5^{3+4+1}=5^8\)
2. \(6^5:\left(6^3.6\right)=6^5:\left(6^{3+1}\right)=6^5:6^4=6^{5-4}=6^1\)
3. \(\left(3^2.3^3.3^4\right):3^7=\left(3^{2+3+4}\right):3^7=3^9:3^7=3^{9-7}=3^2\)
4. \(x^4.x^2.x=x^{4+2+1}=x^7\)
5. \(\left(8^{12}.8^{10}\right).8^3=8^{12+10+3}=8^{25}\)
a,71.2-6.(2x+5)=10^5:10^3
142-6.(2x+5)=10^2
142-6.(2x+5)=100
6.(2x+5)=142-100
6.(2x+5)=42
2x+5=42:6
2x+5=7
2x=7-5
2x=2
x=1
Vậy x=1
a) Ta có: \(\left[\frac{\left(8x-12\right)}{4}\right]\cdot3^3=3^6\)
\(\Leftrightarrow\frac{8x-12}{4}=3^3\)
\(\Leftrightarrow2x-3=3^3\)
\(\Leftrightarrow2x-3=27\)
\(\Leftrightarrow2x=30\)
hay x=15
Vậy: x=15
b) Ta có: \(3^{2+1}+3^x=36\)
\(\Leftrightarrow3^3+3^x=36\)
\(\Leftrightarrow3^x=9\)
hay x=2
Vậy: x=2
c) Ta có: \(2^{x+1}=16\)
\(\Leftrightarrow2^{x+1}=2^4\)
\(\Leftrightarrow x+1=4\)
hay x=3
Vậy: x=3
1.a)
[(8x - 12) : 4] . 33 = 36
(8x - 12) : 4 = 36 : 33 = 33 = 27
8x - 12 = 27 . 4 = 108
8x = 108 + 12 = 120
x = 120 : 8 = 15
b)
32+1 + 3x = 36
27 + 3x = 36
3x = 36 - 27 = 9 = 32
=> x = 2
a) 100 - 7.(x-5) = 68
7.(x - 5) = 100 - 68 = 32
x - 5 = \(\frac{32}{7}\)
x = \(\frac{32}{7}+5=\frac{67}{7}\)
b) 2(x-6)+2227:17=151
2( x -6) + 131 = 151
2 (x - 6) = 20
x - 6 = 20 : 2 = 10
x = 10 + 6 = 16
[( 8.x - 12) : 4 ] . 33 = 36
[( 8.x - 12) : 4 ] = 36 : 33
[( 8.x - 12) : 4 ] = 33
( 8.x - 12) : 4 = 27
8.x - 12 = 27 x 4
8.x - 12 = 108
8.x = 108 + 12
8.x = 120
x = 120 : 8
x = 15