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a) (135 - 35) . (-37) + 37 . (-42 - 58)
= 100 . 0 . (-100)
= 0
b) -65 . (87 - 17) - 87 . (17 - 65)
= -65 . 70 - 87 . (-48)
= -4550 - 135
= -4415
câu 1)
\(\dfrac{-12}{18}+\left(\dfrac{-21}{35}\right)=\dfrac{-19}{15}\)
câu 2)
\(-\dfrac{3}{21}+\dfrac{6}{42}=0\)
câu 3)
\(-\dfrac{18}{24}+\dfrac{15}{21}=-\dfrac{1}{28}\)
câu 4)
\(\dfrac{1}{6}+\dfrac{2}{5}=\dfrac{17}{30}\)
câu 5)
\(\dfrac{3}{5}+\left(-\dfrac{7}{4}\right)=-\dfrac{23}{20}\)
câu 6)
\(\left(-2\right)+\left(\dfrac{-5}{8}\right)=\dfrac{-21}{8}\)
câu 7)
\(\dfrac{1}{-8}+\left(-\dfrac{5}{9}\right)=-\dfrac{49}{72}\)
câu 8)
\(\dfrac{4}{13}+\dfrac{12}{39}=\dfrac{8}{13}\)
câu 9)
\(\dfrac{1}{21}+\dfrac{1}{28}=\dfrac{1}{12}\)
câu 10)
\(-\dfrac{3}{29}+\dfrac{16}{58}=\dfrac{5}{29}\)
câu 11)
\(\dfrac{8}{40}+\left(-\dfrac{36}{45}\right)=-\dfrac{3}{5}\)
câu 12)
\(-\dfrac{8}{18}+\left(-\dfrac{15}{27}\right)=-1\)
câu 13)
\(\dfrac{13}{30}+\left(-\dfrac{1}{5}\right)=\dfrac{7}{30}\)
câu 14)
\(\dfrac{2}{21}+\dfrac{1}{28}=\dfrac{11}{84}\)
câu 15)
\(5+\left(-\dfrac{3}{4}\right)=\dfrac{17}{4}\)
câu 16)
\(\dfrac{18}{24}+\dfrac{45}{-10}=-\dfrac{15}{4}\)
a)= 2021.2021-2020.(2021+1)
= 2021.(2020+1)-2020.(2021+1)
= (2021.2020)+2021-(2020.2021)-2020
= 1
b) B= (1+2-3-4)+(5+6-7-8)+(9+10-11-12)...........+(2017+2018-2019-2020)+2021
B= -4+(-4)+....................(-4)+2021
B= -4x505+2021
B= -2020 + 2021
B = 1
a) \(36.\left(-57\right)-57.64\)
\(=36.\left(-57\right)+\left(-57\right).64=\left(-57\right).\left(36+64\right)\)
\(=\left(-57\right).100=-5700\)
b)\(32.\left(-17\right)+\left(-18\right).17-50.13\)
\(=\left(-32\right).17+\left(-18\right).17-50.13\)
\(=17.\left(-32-18\right)-50.13=17.\left(-50\right)+\left(-50\right).13\)
\(=\left(-50\right).\left(17+13\right)=\left(-50\right).30=-150\)
c)\(-\left(-35\right)+12-|-35|-42\)
\(=35+12-35-42=12-42=-30\)
d)\(\left(-15-12\right):\left(-3\right)^2+5-13.\left(-2\right)+\left(-64\right):2^3\)
\(=-27:9+5+26-64:8=-3+5+26-8=20\)
e)\(\left(135-35\right).\left(-37\right)+37.\left(-42-58\right)=100.\left(-37\right)+37.\left(-100\right)\)
\(=\left(-100\right).37+37.\left(-100\right)=\left(-100\right).\left(37+37\right)\)
\(=\left(-100\right).74=-7400\)
Chúc em học tốt!!!!!!
Answer:
Bài 1:
\(\left(135-35\right).\left(-37\right)+37.\left(-42-58\right)\)
\(=100.\left(-37\right)+37.\left(-100\right)\)
\(=\left(-3700\right)+\left(-3700\right)\)
\(=-7400\)
\(-65.\left(87-17\right)-87.\left(17-65\right)\)
\(=\left(-65\right).87-\left(-65\right).17-87.17+87.65\)
\(=-\left(-65\right).17-87.17\)
\(=17.\left(65-87\right)\)
\(=-374\)
\([3.\left(-2\right)-\left(-8\right)].\left(-7\right)-\left(-2\right).\left(-5\right)\)
\(=[\left(-6\right)+8].\left(-7\right)-\left(-2\right).\left(-5\right)\)
\(=2.\left(-7\right)-10\)
\(=-24\)
Bài 2:
\(\left(-55\right).\left(-25\right).\left(-8\right)\)
\(=\left(-55\right).[\left(-25\right).\left(-8\right)]\)
\(=\left(-55\right).200\)
\(=-11000\)
\(\left(-1\right).\left(-2\right).\left(-3\right).\left(-4\right).\left(-5\right).10\)
\(=[\left(-1\right).10].[\left(-2\right).\left(-5\right)].[\left(-3\right).\left(-4\right)]\)
\(=\left(-10\right).10.12\)
\(=-1200\)
a, [ 58+(-42)]-(58-42)
= 58 - 42 - 58 + 42
= ( 58 - 58 ) + ( 42 - 42)
= 0+0=0
b, ( 65 - 35 ) - ( 35 + 27 )
= 65 - 35 - 35 - 27
= 65 - 70 -27
= 65 - 97
= -32
c, 3 . 52 - 176 : 23
=3 .25 - 176 : 8
= 75 - 22
= 53
d, 22 . 3 - 5 . 23
= 4 . 3 - 5 . 8
= 12 - 40
= -28
g, 2020 - [ 39 - ( 5 - 1 )2 ] - 2019
= 2020 - [ 39 - 42 ] - 2019
= ( 2020 -2019 ) - [ 39 - 16 ]
= 1 - 23
= -22
k, 2018 : [ 38 - ( 7 - 1 )2 ] + 20180
= 2018 : [ 38 - 62 ] + 1
= 2018 : [ 38 - 36 ] + 1
= 2018 : 2 + 1
= 1009 + 1 =1010
a)\(\left[58+\left(-42\right)\right]-\left(58-42\right)\)
=\(58-42-58+42\)
=\(0\)
b)\(\left(65-35\right)-\left(35+27\right)\)
=\(65-35-35+27\)
=\(-32\)
c)\(3.5^2-176:2^3\)
=\(75-22\)
=\(53\)
d)\(2^2.3-5.2^3\)
=\(2^2\left(3-10\right)\)
=\(-28\)
g)\(2020-\left[39-\left(5-1\right)^2\right]-2019\)
=\(1-\left(39-16\right)\)
=\(-22\)
k)\(2018:\left[38-\left(7-1\right)^2\right]+2018^0\)
=\(2018:2+2018^0\)
=\(1010\)