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1/a) 12 - x= 1-(-5)
12 - x = 6
x= 12-6
x=6
b)| x+4|= 12
x+4 = \(\pm\)12
*x+4=12
x=8
*x+4= -12
x=-16
2/Tìm n
\(n-5⋮n+2\)
=> \(n+2-7⋮n+2\)
mà \(n+2⋮n+2\)
=> 7\(⋮\)n+2
=> n+2 \(\varepsilon\)Ư(7)= {1;-1;7;-7}
n+2 | 1 | -1 | 7 | -7 |
n | -1 | -3 | 5 | -9 |
3/a)4.(-5)2 + 2.(-12)
= 2.2.(-5)2 + 2.(-12)
=2[2.25.(-12)]
=2.(-600)
=-1200
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1.Ta có: \(\frac{x}{3}=-\frac{12}{9}\)
=> \(\frac{3x}{9}=-\frac{12}{9}\)
=> 3x = -12
=> x = -12 : 3
=> x = -4
\(\frac{4}{5}x-\frac{8}{5}=-\frac{1}{2}\)
=> \(\frac{4}{5}x=-\frac{1}{2}+\frac{8}{5}\)
=> \(\frac{4}{5}x=\frac{11}{10}\)
=> \(x=\frac{11}{10}:\frac{4}{5}\)
=> \(x=\frac{11}{8}\)
\(-\frac{9}{11}\cdot\frac{3}{8}-\frac{9}{11}\cdot\frac{5}{8}+\frac{17}{11}=-\frac{9}{11}\left(\frac{3}{8}+\frac{5}{8}\right)+\frac{17}{11}=-\frac{9}{11}\cdot1+\frac{17}{11}=1\)
\(\frac{2}{1.3}+....+\frac{2}{53.55}=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{53}-\frac{1}{55}=1-\frac{1}{55}=\frac{54}{55}\)
\(x+5-\frac{1}{2}=3\frac{1}{2}\)
\(x+5=3.5+0.5=4\)
\(x=4-5=-1\)
\(3^{x+1}=27=3^3\)
\(x+1=3\)
vậy x=2
1/
\(A\)dương \(\Leftrightarrow\)\(\hept{\begin{cases}\left(x-\frac{1}{2}\right)>0\\x-\frac{4}{5}>0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x>0+\frac{1}{2}\\x>0+\frac{4}{5}\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x>\frac{1}{2}\\x>\frac{4}{5}\end{cases}}\Leftrightarrow x>0,8\)
2/ Làm tương tự nhưng có 2 trường hợp nên bạn làm từng trường hợp nhé ..!
a,3x-10=2x+13
\(\Rightarrow\)3x-2x=10+13
\(\Rightarrow\)x=23
b,x+12=-5-x
\(\Rightarrow\)x+x=-12-5
\(\Rightarrow\)2x=-17
\(\Rightarrow\)x=-8,5
c,x+5=10-x
\(\Rightarrow\)x+x=-5+10
\(\Rightarrow\)2x=5
\(\Rightarrow\)x=2,5
e,12-x=x+1
\(\Rightarrow\)-x-x=-12+1
\(\Rightarrow\)-2x=-11
\(\Rightarrow\)x=5,5
f,14+4x=3x+20
\(\Rightarrow\)4x-3x=-14+20
\(\Rightarrow\)x=6
g,2.(x-1)+3(x-2)=x-4
\(\Rightarrow\)2x-2+3x-6=x-4
\(\Rightarrow\)2x-2+3x-6-x+4=0
\(\Rightarrow\)4x-4=0
\(\Rightarrow\)4x=4
\(\Rightarrow\)x=1
h,3(4-x)-2(x-1)=x+20
\(\Rightarrow\)12-3x-2x+2-x-20=0
\(\Rightarrow\)-6x-6=0
\(\Rightarrow\)-6x=6
\(\Rightarrow\)x=-1
i,4(2x+7)-3(3x-2)=24
\(\Rightarrow\)8x+28-9x+6=24
\(\Rightarrow\)-x+34=24
\(\Rightarrow\)-x=-10
\(\Rightarrow\)x=10
k,3(x-2)+2x=10
\(\Rightarrow\)3x-6+2x=10
\(\Rightarrow\)5x-6=10
\(\Rightarrow\)5x=16
\(\Rightarrow\)x=3,2
Phần d, tớ không biết làm!!!!
a) 2.(x-5) - 3.(x+7) = 14
2.x - 10 - 3.x - 21 = 14
2.x - 3.x - (10+21) = 14
-x - 31 = 14
-x = 45
x = -45
phần b bn cx lm tương tự như phần a nha!
c) 5- (x+7) = 4
5 - x - 7 = 4
5-7 -x = 4
-2 -x = 4
x = -6
câu d lm giống câu c
a) 2.(x-5) - 3.(x+7) = 14
2.x - 10 - 3.x - 21 = 14
2.x - 3.x - (10+21) = 14
-x - 31 = 14
-x = 45
x = -45
a) 122 + ( 518 - x ) = -36
144 + ( 518 - x ) = -36
158 - x = -36 - 144
158 - x = -180
x = 158 - (-180)
x = 338
b) 2 ( x - 5 ) = 8
x - 5 = 8 : 2
x - 5 = 4
x = 4 + 5
x = 9
a) \(12^2+\left(518-x\right)=-36\)
\(144+518-x=-36\)
\(662-x=-36\)
\(x=662+36\)
\(x=698\)
vậy \(x=698\)
b) \(2\left(x-5\right)=8\)
\(x-5=4\)
\(x=9\)
vậy \(x=9\)