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\(a;\dfrac{2}{3}x-50\%x-\left(-\dfrac{4}{5}\right):1\dfrac{3}{5}=-0,12+1\dfrac{3}{25}\\ \dfrac{1}{6}x+\dfrac{1}{2}=1\Rightarrow\dfrac{1}{6}x=1-\dfrac{1}{2}=\dfrac{1}{2}\\ \Rightarrow x=\dfrac{1}{2}:\dfrac{1}{6}=3\\ b;\left(-1\dfrac{1}{6}+\dfrac{2}{3}-\dfrac{3}{4}\right):x+\left(-1\dfrac{11}{12}\right)\cdot1\dfrac{21}{23}=-6\dfrac{1}{3}\\ -\dfrac{5}{4}:x-\dfrac{11}{3}=-\dfrac{19}{3}\\ -\dfrac{5}{4}:x=-\dfrac{19}{3}+\dfrac{11}{3}=-\dfrac{8}{3}\\ x=-\dfrac{5}{4}:\left(-\dfrac{8}{3}\right)=\dfrac{15}{32}\\ c;50\%x-\dfrac{1}{3}x-\left(-\dfrac{2}{3}\right)^2\cdot\left(-1\dfrac{1}{8}\right)=-119\dfrac{3}{4}+120\dfrac{5}{6}\\ \dfrac{1}{6}x+\dfrac{1}{2}=\dfrac{13}{12}\Rightarrow\dfrac{1}{6}x=\dfrac{13}{12}-\dfrac{1}{2}=\dfrac{7}{12}\\ x=\dfrac{7}{12}:\dfrac{1}{6}=\dfrac{7}{2}\)
\(x:(3\frac{1}{2}-5\frac{1}{6})=4\frac{1}{5}-6\frac{2}{3}\) b,\((2\frac{1}{3}+3\frac{1}{2})\cdot x=-4\frac{1}{4}+3\frac{1}{7}\)
\(x:\frac{-5}{3}\)=\(\frac{-37}{15}\) \(\frac{35}{6}\cdot x=\)\(\frac{-31}{28}\)
\(x=\frac{-37}{15}\cdot\frac{-5}{3}\) \(x=\frac{-31}{28}:\)\(\frac{35}{6}\)
\(x=\frac{37}{9}\) \(x=\frac{-93}{490}\)
Vậy x=\(\frac{37}{9}\) Vậy x=\(\frac{-93}{490}\)
7,5x:\((9-6\frac{13}{21})=2\frac{13}{25}\)
7,5x:\(\frac{50}{21}\)=\(\frac{63}{25}\)
7,5x=\(\frac{63}{25}:\frac{50}{21}=\frac{1323}{1250}\)
x=\(\frac{1323}{1250}:7,5\)
x=\(\frac{441}{3125}\)
Vậy x=\(\frac{441}{3125}\)