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( 3x + 1 )\(^3\)= 64
( 3x + 1 )\(^3\)= 4\(^3\)
=> 3x + 1 = 4
3x = 4 - 1
x = 3 : 3
x = 1
Vậy, x = 1
`#040911`
`(x + 5)^3 = (2x)^3`
`\Rightarrow x + 5 = 2x`
`\Rightarrow x + 5 - 2x = 0`
`\Rightarrow 5 + (x - 2x) = 0`
`\Rightarrow 5 - x = 0`
`\Rightarrow x = 5 - 0`
`\Rightarrow x = 5`
Vậy, `x= 5.`
a) \(1,25^2-0,5^2+3,25^3\)
\(=\left(\frac{5}{4}\right)^2-\left(\frac{1}{2}\right)^2+\left(\frac{13}{4}\right)^3\)
\(=\frac{25}{16}-\frac{1}{4}+\frac{2197}{64}\)
\(=\frac{2281}{64}\)
b) \(1,2+2,4^2-\left(3\frac{1}{2}\right)^2\)
\(=\frac{6}{5}+\left(\frac{12}{5}\right)^2-\left(\frac{7}{2}\right)^2\)
\(=\frac{6}{5}+\frac{144}{25}-\frac{49}{4}\)
\(=\frac{-529}{100}\)
2.2.2.5.5.5.10 = ( 2.5 ) . ( 2.5 ) . ( 2.5 ) . 10 = 10 . 10 . 10 . 10 = 104
2 . 2 . 2 . 2 . 4 . 4 = ( 2.2 ) . ( 2.2 ) . 4 . 4 = 4 . 4 . 4 . 4 = 44
4 . 4 . 8 . 8 = (2 . 2 ) . ( 2.2 ) . ( 2 . 2 . 2 ) . ( 2. 2 . 2 ) = 2 . 2 .2 . 2 .2 . 2 .2 . 2 .2 . 2 = 210
x3 = 125
x = \(\sqrt[3]{125}=5\)
2x + 4.2x = 5.25
2x ( 4 + 1 ) = 25 . 5
2x . 5 = 25 . 5
x = 5
3n : 9 = 37
3n : 32 = 37
3n-2 = 37
n - 2 = 7
n = 7 + 2 = 9
n = { 3 ; 4 ; 5 }
(5x + 9 )3= 216
(5x + 9 )3= 63
=> 5x+ 9 = 6
5x = 6 - 9
5x = - 3
x = -3 : 5
x = \(\frac{-3}{5}\)
a) 2840 + [(999 - 9x) : 60 ] .24 = 3200
=> [(999-9x) : 60 ] . 24 = 2840 - 3200 = -360
=> (999 - 9x) = \(\frac{-360}{24}=-15\)
=> 9x = 999 - ( - 15) = 999 + 15 = 1014
=> x = \(\frac{1014}{9}=\frac{338}{3}\)
b) (3x - 48) . 6 = 33.22 - 23.32
(3x - 48) . 6 = 27 . 4 - 8 . 9
(3x -48).6 = 36
(3x - 48 = 36 : 6 = 6
3x = 54
x = 54 : 3 =18
t ick cho mik nha
\(\left(9-x\right)^3=64\)
\(\left(9-x\right)^3=4^3\)
\(\Leftrightarrow9-x=4\)
\(x=5\)
(9-x)3 = 64
=> 9-x = 4
=>x = 5