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[( 8x - 12 ) : 4 ] . 33 = 36
[ ( 8x - 12 ) : 4 ] = 12/11
( 8x - 12 ) = 12/11 . 4
( 8x - 12 ) = 48/11
8x = 48/11 + 12
8x = 180/11
x = 45/22
\(\left[\left(8x-12\right):4\right].33=36\)
\(\left(8x-12\right):4=\frac{12}{11}\)
\(8x-12=\frac{48}{11}\)
\(8x=\frac{180}{11}\)
\(x=\frac{45}{22}\approx2,045\)
\(30-\left[4.\left(x-2\right)+15\right]=3\)
\(4.\left(x-2\right)+15=27\)
\(4.\left(x-2\right)=12\)
\(x-2=3\)
\(x=5\)
a.219 - 7(x+1) = 100
7(x+1) = 219 - 100
7(x+1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
b. (3x - 6 ) . 3 = 36
3x - 6 = 36 : 3
3x - 6 = 12
3x = 12 + 6
3x = 18
x = 18 : 3
x = 6
c.716 - ( x-143) = 659
x-143 = 716 - 659
x-143 = 57
x = 57 + 143
x = 200
b. 30 - [4(x-2)+15] = 3
4(x-2) + 15 = 30 - 3
4(x-2)+15 = 27
4(x-2) = 27 - 15
4(x-2) = 12
x-2 = 12 : 4
x-2 = 3
x = 2 + 3 = 5
e.[(8x - 12) : 4] .33 = 36
[(8x - 12) : 4] . 27 = 729
(8x - 12) : 4 = 729 : 27 = 27
8x - 12 = 27 . 4 = 108
8x = 108 + 12 = 120
x = 120 : 8 = 15
a) \(\Leftrightarrow7\left(x+1\right)=119\\ \Leftrightarrow x+1=17\\ \Leftrightarrow x=16\)
b) \(\Leftrightarrow9\left(x-2\right)=36\\ \Leftrightarrow x-2=4\\ \Leftrightarrow x=6\)
c) \(\Leftrightarrow x-143=57\\ \Leftrightarrow x=200\)
d) \(\Leftrightarrow4\left(x-2\right)+15=27\\ \Leftrightarrow4\left(x-2\right)=12\\ \Leftrightarrow x-2=3\\ \Leftrightarrow x=5\)
e) \(\Leftrightarrow\left(2x-3\right).4:4=3^3\\ \Leftrightarrow2x-3=27\\ \Leftrightarrow2x=24\\ \Leftrightarrow x=12\)
1: Ta có: \(20-2\left(x+4\right)=4\)
\(\Leftrightarrow2\left(x+4\right)=16\)
\(\Leftrightarrow x+4=8\)
hay x=4
5: Ta có: \(\left(x+1\right)^3=27\)
\(\Leftrightarrow x+1=3\)
hay x=2
11: Ta có: \(\left(x+3\right)^3=125\)
\(\Leftrightarrow x+3=5\)
hay x=2
12: Ta có: \(\left(2x\right)^4=16\)
\(\Leftrightarrow x^4=1\)
hay \(x\in\left\{1;-1\right\}\)
a: \(=\dfrac{-1}{4}+\dfrac{7}{33}-\dfrac{5}{3}-\dfrac{5}{4}-\dfrac{6}{11}+\dfrac{48}{49}\)
\(=\dfrac{-3}{2}+\dfrac{7}{33}-\dfrac{18}{33}-\dfrac{5}{3}+\dfrac{48}{49}\)
\(=\dfrac{-9-10}{6}+\dfrac{-11}{33}+\dfrac{48}{49}\)
\(=\dfrac{-19}{6}+\dfrac{-1}{3}+\dfrac{48}{49}=-\dfrac{247}{98}\)
b: \(=\dfrac{11}{125}-\dfrac{17}{18}+\dfrac{4}{9}-\dfrac{5}{7}+\dfrac{17}{14}\)
\(=\dfrac{11}{125}+\dfrac{-17+8}{9}+\dfrac{-10+17}{14}\)
\(=\dfrac{11}{125}-1+\dfrac{7}{14}=\dfrac{11}{125}+\dfrac{1}{2}=\dfrac{22+125}{250}=\dfrac{147}{250}\)
\(\left[\left(8x-12\right):4\right].3^3=3^6\)
\(\Leftrightarrow\left(8x-12\right):4=3^3\)
\(\Leftrightarrow2x-3=27\Leftrightarrow2x=30\Leftrightarrow x=15\)
Ta có: (8x - 12)3 = 125
=> (8x - 12)3 = 53
=> 8x - 12 = 5
=> 8x = 5 + 12
=> 8x = 17
=> x = 17/8
\(3^3=27;3^6=729\)
\(\left(8X-12\right):4=729:27\)
\(\left(8X-12\right):4=27\)
\(8X-12=27.4\)
\(8X-12=108\)
\(8X=108+12\)
\(8X=120\)
\(X=120:8\)
\(X=15\)
-[(8x - 12):4] .33=36
[(8x - 12):4] = 36:33
[(8x - 12):4] = 33
(8x - 12):4 = 27
8x - 12 = 27 x 4
8x - 12 = 108
8x = 108 + 12
8x = 120
x = 120 : 8
x = 15
-4x3+15=47
4x3 = 47-15
4x3 = 32
x3 = 32:4
x3 = 8
x = 2
-4.2x-3=125
4.2x = 125 + 3
4.2x = 128
2x = 128:4
2x = 32
x = 32:2
x = 16