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Ta có: \(\frac{131313}{565656}=\frac{131313:10101}{565656:10101}=\frac{13}{56}\)
\(\frac{131313}{727272}=\frac{13}{72}\)
\(\frac{131313}{909090}=\frac{13}{90}\)
\(\Rightarrow C=70\left(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\right)=70\left(\frac{39}{79}\right)=39\)
Vậy C = 39
C=70(\(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\))=70\(\frac{39}{70}\)=39
\(70.\left(\frac{252525}{565656}+\frac{252525}{727272}+\frac{252525}{909090}\right)\)
\(=70.\left(\frac{25}{56}+\frac{25}{72}+\frac{25}{90}\right)\)
\(=70.25.\left(\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\right)\)
\(=1750.\left(\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\right)\)
\(=1750.\left(\frac{1}{7}-\frac{1}{10}\right)\)
\(=1750.\frac{3}{70}\)
\(=75\)
Tính :
\(=70.\left(\frac{25}{56}+\frac{25}{72}+\frac{25}{90}\right)\)
=\(70.\frac{15}{14}\)
=75
knha
\(B=70\left(\frac{131313}{565656}+\frac{131313}{727272}+\frac{131313}{909090}\right)\)
\(B=70\left(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\right)\)
\(B=70.13\left(\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\right)\)
\(B=70.13.\frac{3}{70}\)
\(B=39\)
\(B=70\left(\frac{131313}{565656}+\frac{131313}{727272}+\frac{131313}{909090}\right)\)
\(=70\left(\frac{13.10101}{56.10101}+\frac{13.10101}{72.10101}+\frac{13.10101}{90.10101}\right)\)
\(=70\left(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\right)\)
\(=70.13\left(\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\right)\)
\(=910\left(\frac{45}{2520}+\frac{35}{2520}+\frac{28}{2520}\right)\)
\(=910.\frac{3}{70}\)
\(=39\)
Vậy \(B=39\)
\(\left(15-6\frac{13}{18}\right):11\frac{1}{27}-2\frac{1}{8}:1\frac{11}{40}\\ =\left(\frac{270}{18}-\frac{121}{18}\right):\frac{298}{27}-\frac{17}{8}:\frac{51}{40}\\ =\frac{149}{18}\cdot\frac{27}{298}-\frac{17}{8}\cdot\frac{40}{51}\\ =\frac{3}{4}-\frac{5}{3}\\ =\frac{9}{12}-\frac{20}{12}=\frac{-11}{12}\)
\(70\cdot\left(\frac{131313}{565656}+\frac{131313}{727272}+\frac{131313}{909090}\right)\\ =70\cdot\left(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\right)\\ =70\cdot13\cdot\left(\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\right)\\ =910\cdot\left(\frac{45}{2520}+\frac{35}{2520}+\frac{28}{2520}\right)\\ =910\cdot\frac{3}{70}=39\)
\(\frac{121212}{171717}+\frac{2}{17}-\frac{40}{171}\)
\(=\frac{12}{17}+\frac{2}{17}-\frac{4}{17}=\frac{10}{17}\)
\(\Rightarrow A=B=\frac{10}{17}\)
121212/171717 + 2/7 - 40/171
= 12/17 + 2/7 - 4/17 = 10/17
= A = B = 10/17
Ta có \(70\left(\frac{121212}{565656}+\frac{121212}{727272}+\frac{121212}{909090}\right)\)
\(=70\left(\frac{3\cdot40404}{14\cdot40404}+\frac{121212}{121212\cdot6}+\frac{2\cdot60606}{15\cdot60606}\right)\)
\(=70\left(\frac{3}{14}+\frac{1}{6}+\frac{2}{15}\right)\)
\(=70\cdot\frac{18}{35}=36\)