
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a) 6x + x = 511 : 59 + 31
6x + x = 52 + 31
7x = 25 + 3
7x = 28
x = 28 : 7
x = 4
b) 7x - x = 521 : 59 + 3 . 22 - 70
6x = 512 + 3 . 4 - 1
6x = 244140625 + 12 - 1
6x = 244140636
x = 244140636 : 6
x = 40690106
a)6x +x = 511 :59 +31
(6+1)x=52 +3
7x =25 +3=28
x = 28 :7
x=4
Vậy x=4
b) 7x-x = 521 : 59 +3 . 22 - 7
(7-1)x = 512 +3.4-1
6x= 244140625 + 12 - 1
6x = 244140637-1=244140636
x=244140636:6
x=40690106
Vậy x= 40690106

6x+x=5^11:5^9+3^1
x.(6+1)=5^2+3
x.7=25+3
x.7=28
x=28:7
x=4
vậy x=4
k mk nha

Tìm x :
\(5x+x=39-3^{11}:3^9\)
\(6x=39-3^2\)
\(6x=39-9\)
\(6x=30\)
\(x=30:6\)
\(x=5\)
Thực hiện phép tính :
\(225:3^2+4^3.125-125:5^2\)
\(=225:9+64.125-125:25\)
\(=25+8000-5\)
\(=8020\)
a, 6x=39-3^2 b,225:9+64.125-125:25
6x=39-9 =25+64.125-125:25
6x=30 =25+8000-125:25
x=30:6 =25+8000-5
x=5 =8020

\(5x+2x=6^2-5^0\Leftrightarrow5x+2x=6^2-1\)
\(\Leftrightarrow5x-2x=36-1\Leftrightarrow5x-2x=35\Leftrightarrow x\left(5+2\right)=35\)
\(\Leftrightarrow7x=35\Leftrightarrow x=35:7\Leftrightarrow x=5\)
\(5x+x=150:2+3\Leftrightarrow5x+x=75+3\)
\(\Leftrightarrow5x+x=78\Leftrightarrow x\left(5+1\right)=78\Leftrightarrow x6=78\)
\(\Leftrightarrow x=78:6\Leftrightarrow x=13\)
a) 5x + 2x = 62 - 50
7x = 35 => x = 5
b) 5x + x = 150 : 2 + 3
6x = 78 => x = 13
c) 6x + x = 511 : 59 + 31
7x = 28 => x = 4
d) 5x + 3x = 36 : 33 x 4 + 12
8x = 120 => x = 15
e) 4x + 2x = 68 - 219 : 216
6x = 60 => x = 10
f) 5x + x = 39 - 311 : 39
6x = 30 => x = 5
g) 7x - x = 521 : 519 + 3 x 22 - 70
6x = 36 => x = 6
h) 7x - 2x = 617 : 615 + 44 : 11
5x = 40 => x = 8

a,\(\left(25^{11}.5^9\right):\left(5^{46}.625\right)\)
\(=\left(5^{42}.5^9\right):\left(5^{46}.5^4\right)\)
\(=5^{51}:5^{50}=5\)
b,\(\left(3^{2011}+3^{2009}\right):3^{2000}:9^4\)
\(=\left(3^{2009}.\left(3^2+1\right)\right):3^{2000}:3^8\)
\(=3^{2009}.10:3^{2008}\)
\(=3.10=30\)

1,7x=5^2+3
7x=28
x=28:7
x=4
mấy câu còn lại tương tự như vậy thôi,5x+3x=8x;4x+2x=6x;5x+x=6x

Ta có:
\(A=1^{11}+2^{11}+3^{11}+...+9^{11}\)
\(1^{11}+9^{11}\equiv1^{11}+\left(-1\right)^{11}\left(mod10\right)\equiv0\left(mod10\right)\)
\(2^{11}+8^{11}\equiv2^{11}+\left(-2\right)^{11}\left(mod10\right)\equiv0\left(mod10\right)\)
\(3^{11}+7^{11}\equiv3^{11}+\left(-3\right)^{11}\left(mod10\right)\equiv0\left(mod10\right)\)
\(4^{11}+6^{11}\equiv4^{11}+\left(-4\right)^{11}\left(mod10\right)\equiv0\left(mod10\right)\)
\(5^{11}⋮5\)
Do đó \(A⋮5\).
\(1^{11}+8^{11}\equiv1^{11}+\left(-1\right)^{11}\left(mod9\right)\equiv0\left(mod9\right)\)
\(2^{11}+7^{11}\equiv2^{11}+\left(-2\right)^{11}\left(mod9\right)\equiv0\left(mod9\right)\)
\(3^{11}+6^{11}\equiv3^{11}+\left(-3\right)^{11}\left(mod9\right)\equiv0\left(mod9\right)\)
\(4^{11}+5^{11}\equiv4^{11}+\left(-4\right)^{11}\left(mod9\right)\equiv0\left(mod9\right)\)
\(9^{11}⋮9\)
suy ra \(A⋮9\).
Mà \(\left(5,9\right)=1\)nên \(A\)chia hết cho \(5.9=45\).
Ta có đpcm.
\(6x=39-3^{11}:3^9\)
\(\Rightarrow6x=39-3^2=39-9=30\)
\(\Rightarrow6x=30\)
\(\Rightarrow x=30:6=5\)
Vậy x = 5