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17 tháng 3 2022

\(\frac{6}{5}< \frac{x}{10}< \frac{3}{2}\)

\(\Leftrightarrow\frac{12}{10}< \frac{x}{10}< \frac{15}{10}\)

\(\Leftrightarrow12< x< 15\)

\(\Leftrightarrow x\in\left\{13;14\right\}\)

Vậy....

17 tháng 3 2022

13 và 14 nhé!

2 tháng 9 2021

thiếu r

19 tháng 1 2022

a, thiếu đề 

b, -5 ( 2 - x ) + 4 ( x - 3 ) = 10x - 15 

<=> -10 + 5x + 4x - 12 = 10x - 15 

<=> -x = 7 <=> x = 7 

c,-7(5-x)-2(x-10)=15

<=> -35 + 7x - 2x + 20 = 15 <=> 5x = 30 <=> x = 6 

d, -4(x+1) + 89x - 3 = 24 

<=> 85x = 31 <=> x = 31/85 

e, 5(x-30-2(x+6)) = 9 

<=> 5 (-x-49) = 9 <=> -5x = 254 <=> x = -254/5 

b: =>-10+5x+4x-12=10x-15

=>9x-10x=-15+22

=>-x=7

hay x=-7

c: =>-35+7x-2x+20=15

=>5x-15=15

=>x=6

d: =>-4x-4+72x-24=24

=>68x-32=24

hay x=14/17

19 tháng 8 2021

Đặt A=22+23+..+22005
 
2A=23+24+..+22006
suy ra 2A-A=(23+24+..+22006) - (22+23+..+22005)
A=22006-22
suy ra C=4+22006-4
           C=22006    .Là lũy thừa của 2 (đpcm)

 

19 tháng 8 2021

C=4+22+23+...+22005

2C=8+23+24+...+22006

2C-C=(8+23+24+...+22006)-(4+22+23+...+22005)

C=4+22005-22

C=22-22+22005

C=22005(đpcm)

5 tháng 11 2023

\(41\cdot36+36\cdot59+400\)

\(=36\cdot\left(41+59\right)+400\)

\(=36\cdot100+400\)

\(=3600+400\)

\(=4000\)

___________

\(3^3-2^3:2+11\cdot5^2\)

\(=27-8:2+11\cdot25\)

\(=27-4+\left(10+1\right)\cdot25\)

\(=27-4+250+25\)

\(=23+275\)

\(=298\)

7 tháng 3 2021

a) \(\dfrac{x}{5}=\dfrac{2}{5}\)

\(\Rightarrow5x=10\)

\(\Leftrightarrow x=2\)

Vậy x = 2

b) ĐKXĐ: \(x\ne0\)

 \(\dfrac{3}{-8}=\dfrac{6}{-x}\)

\(\Rightarrow-3x=-48\)

\(\Leftrightarrow x=16\)

Vậy x = 16

c) \(\dfrac{1}{9}=\dfrac{-2x}{10}\)

\(\Rightarrow-18x=10\)

\(\Leftrightarrow x=-\dfrac{5}{9}\)

Vậy \(x=-\dfrac{5}{9}\)

d) ĐKXĐ: \(x\ne0\)

 \(\dfrac{3}{x}-5=\dfrac{-9}{x}+2\)

\(\Leftrightarrow\dfrac{3-5x}{x}=\dfrac{-9+2x}{x}\)

\(\Rightarrow3-5x=-9+2x\)

\(\Leftrightarrow7x=12\)

\(\Leftrightarrow x=\dfrac{12}{7}\)

Vậy \(x=\dfrac{12}{7}\)

e) ĐKXĐ: \(x\ne0\)

 \(\dfrac{x}{-2}=\dfrac{-8}{x}\)

\(\Rightarrow x^2=16\)

\(\Leftrightarrow x=\pm4\)

Vậy \(x=\pm4\)

 

a) Ta có: \(\dfrac{x}{5}=\dfrac{2}{5}\)

\(\Leftrightarrow x=\dfrac{2\cdot5}{5}=2\)

Vậy: x=2

b) Ta có: \(\dfrac{3}{-8}=\dfrac{6}{-x}\)

\(\Leftrightarrow-x=\dfrac{6\cdot\left(-8\right)}{3}=-16\)

hay x=16

Vậy: x=16

31 tháng 1 2018

\(-2\left(x-1\right)+\left(-6\right)=10\)

\(-2\left(x-1\right)=10-\left(-6\right)\)

\(-2\left(x-1\right)=16\)

\(x-1=16:\left(-2\right)\)

\(x-1=-8\)

\(x=-8+1\)

\(x=-7\)

31 tháng 1 2018

\(-2\left(x-1\right)+\left(-6\right)=10\)

\(-2.\left(x-1\right)=10-\left(-6\right)\)

\(-2\left(x-1\right)=16\)

\(x-1=16:\left(-2\right)\)

\(x-1=-8\)

\(x=\left(-8\right)+1\)

\(x=-7\)

16 tháng 8 2023

a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)

\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)

\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)

\(\Rightarrow x=\dfrac{-5}{12}\)

b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)

\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)

\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{2}{5}\)

c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)

\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)

\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)

\(\Rightarrow x=\dfrac{-77}{120}\)

d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)

\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)

\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)

\(\Rightarrow x=\dfrac{-7}{20}\)

e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)

\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)

\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)

\(\Rightarrow x=\dfrac{-59}{105}\)

16 tháng 8 2023

g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)

\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)

\(\Rightarrow x=\dfrac{-13}{12}\)

16 tháng 8 2023

a) \(\dfrac{1}{2}-\left(x+\dfrac{1}{3}\right)=\dfrac{5}{6}\)

\(\Rightarrow x+\dfrac{1}{3}=\dfrac{1}{2}-\dfrac{5}{6}\)

\(\Rightarrow x+\dfrac{1}{3}=\dfrac{-1}{3}\)

\(\Rightarrow x=\dfrac{-1}{3}-\dfrac{1}{3}\)

\(\Rightarrow x=\dfrac{-2}{3}\)

b)\(\dfrac{3}{4}-\left(x+\dfrac{1}{2}\right)=\dfrac{4}{5}\)

\(\Rightarrow x+\dfrac{1}{2}=\dfrac{3}{4}-\dfrac{4}{5}\)

\(\Rightarrow x+\dfrac{1}{2}=\dfrac{-1}{20}\)

\(\Rightarrow x=\dfrac{-1}{20}-\dfrac{1}{2}\)

\(\Rightarrow x=\dfrac{-11}{20}\)

16 tháng 8 2023

c) \(\dfrac{3}{35}-\left(\dfrac{3}{5}+x\right)=\dfrac{2}{7}\)

\(\Rightarrow\dfrac{3}{5}+x=\dfrac{3}{35}-\dfrac{2}{7}\)

\(\Rightarrow\dfrac{3}{5}+x=\dfrac{-1}{5}\)

\(\Rightarrow x=\dfrac{-1}{5}-\dfrac{3}{5}\)

\(\Rightarrow x=\dfrac{-4}{5}\)

d)\(\dfrac{2}{3}.x=\dfrac{4}{27}\)

\(\Rightarrow x=\dfrac{4}{27}:\dfrac{2}{3}\)

\(\Rightarrow x=\dfrac{2}{9}\)

e) \(\dfrac{-3}{5}.x=\dfrac{21}{10}\)

\(\Rightarrow x=\dfrac{21}{10}:\dfrac{-3}{5}\)

\(\Rightarrow x=\dfrac{-7}{2}\)

A. x = 2

B. \(\dfrac{3}{8}=\dfrac{6}{x}\)\(\Leftrightarrow x=\dfrac{6.8}{3}=16\)

C. x = 3

D. \(x=\dfrac{4.6}{8}=3\)

E. \(x=\dfrac{7}{3}\)

G.\(\dfrac{14}{13}=\dfrac{28}{10-x}\)

<=>\(14\left(10-x\right)=364\)

<=> 10 - x = 26 

<=> x = -16 

H. \(3\left(x+2\right)=4\left(x-5\right)\)

<=> 3x + 6  = 4x - 20 

<=> -x = -26

<=> x = 26

K. \(\dfrac{x}{2}=\dfrac{8}{x}\)

<=> \(x^2=16\)

<=> \(\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)

M. \(\left(x-2\right)^2=100\)

<=> \(\left[{}\begin{matrix}x-2=10\\x-2=-10\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-8\end{matrix}\right.\)

5 tháng 1 2023

a=2

b=16

c=3

d=3

mik chỉ biết thế này thôi(ko chắc đúng=3)