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\(\Leftrightarrow5^x\cdot625-3\cdot5^x\cdot125=2\cdot5^{11}\)
\(\Leftrightarrow5^x\cdot250=2\cdot5^{11}\)
\(\Leftrightarrow5^x=5^8\)
hay x=8
a) \(2.5^2.3^2+\left\{\left[2.5^3-\left(5x+4\right).5\right]:\left(2^2.3.5\right)\right\}=453\)
\(2.25.9+\left\{\left[2.125-\left(5x+4\right).5\right]:\left(4.3.5\right)\right\}=453\)
\(50.9+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(450+\left\{\left[250-\left(5x+4\right).5\right]:60\right\}=453\)
\(\left[250-\left(5x+4\right).5\right]:60=453-450\)
\(\left[250-\left(5x+4\right).5\right]:60=3\)
\(250-\left(5x+4\right).5=3.60\)
\(250-\left(5x+4\right).5=180\)
\(\left(5x+4\right).5=250-180\)
\(\left(5x+4\right).5=70\)
\(5x+4=70:5\)
\(5x+4=14\)
\(5x=14-4\)
\(5x=10\)
\(x=10:5\)
\(x=2\)
Vậy \(x=2\)
b) \(\left|x-\frac{1}{3}\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{1}{3}=-2\\x-\frac{1}{3}=2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\left(-2\right)+\frac{1}{3}\\x=2+\frac{1}{3}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-5}{3}\\x=\frac{7}{3}\end{cases}}\)
Vậy \(x\in\left\{\frac{-5}{7};\frac{7}{3}\right\}\)
5x-11 - 2.52 = 3.53
5x-11 - 2.25 = 3.125
5x-11 - 50 = 375
5x-11 = 375 + 50
5x-11 = 425
.....
=>x thuộc rỗng nhé
5x-11-2.25=3.125
5x-11-50=375
5x-11=375+50
5x-11=425
đề sai rồi vì 5 mũ mấy cũng ko bằng 425 đâu
Ta có:\(5^{x+4}-3\cdot5^{x+3}=2\cdot5\)
\(5^x\cdot5^4-3\cdot5^x\cdot5^3=10\)
\(5^x\left(5^4-3\cdot5^3\right)=10\)
\(5^x\cdot250=10\)
\(5^x=10:250\)
\(5^x=\frac{1}{25}\)
\(5^x=5^{-2}\)
\(\Rightarrow x=-2\)
\(5^{x+4}-3.5^{x+3}=2.5\)
\(\Rightarrow5^{x+3}.5-3.5^{x+3}=2.5\)
\(\Rightarrow5^{x+3}.\left(5-3\right)=2.5\)
\(\Rightarrow5^{x+3}.2=2.5\)
\(\Rightarrow5^{x+3}=5\)
\(\Rightarrow x+3=1\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)