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\(=\dfrac{5871}{928-\left(247-410\right)}=\dfrac{5871}{928-247+410}\)
\(=\dfrac{5871}{1091}\)
\(5871:\left[928-\left(247-82\cdot5\right)\right]\)
\(=5871:\left[928-\left(247-410\right)\right]\)
\(=5871:\left(928+163\right)\)
\(=5871:1091\)
\(=\dfrac{5871}{1091}\)
\(=5871:\left[928-\left(247-410\right)\right]\)
\(=5871:\left(928+163\right)\)
\(=5871:1091\)
\(=\frac{5871}{1091}\)
tíc mình nha
5871⁰ : [928 - (247 - 82).5] + 2175⁰
= 1 : (928 - 165.5) + 1
= 1 : (928 - 825) + 1
= 1 : (-103) + 1
= 102/103
\(=5871:\left[928-165\cdot5\right]\\ =5871:\left[928-825\right]=5871:103=57\)
\(=5871:\left[928-165.5\right]=5871:\left[928-825\right]=5871:103=57\)
5871:{928-[(-82)+247].5}
=5871:{928-165.5}
=5871:{928-825}
=5871:103
=57
5871:{928-[(-82)+247)].5}
=5871:{928-165}.5
=5871:763.5
=5871:3816
=???????
5871:[928-(247-82.5)]
=5871:[928-(247-410)]
=5871:[928-(-163)]
=5871:(928+163)
=5871:1091
=5.381301558
=
a)160-(23.52-6.25)
160-(1196-150)
160-1046
-886
b)4.52-32:24
208-4/3
620/3
c)5871:(928-(247-82).5)
5871:(928-165.5)
5871:(928-825)
5871:103
57
A, 160-(2^3.5^2-6.25)
160-50
=110
=> 110= 2.5.7
B,4.5^2-32:2^4
=4.25-32:16
=100-2
=98
=>98=2.7^2
Cau c mk giong kq vs bn tren
\(5871:\left[928-\left(247-82.5\right)\right]\\ =5871:\left[928-\left(247-410\right)\right]\\ =5871:\left[928-\left(-163\right)\right]\\ =5871:1091\\ =\dfrac{5871}{1091}\)
5871/1091