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S=5+5^2+5^3+5^4+...+5^2010
=(5+5^4)+(5^2+5^5)+(5^3+5^6)+...+(5^2007+5^2010)
=5(1+5^3)+5^2(1+5^3)+5^3(1+5^3)+...+5^2007(1+5^3)
=5*126+5^2*126 +5^3+126+...+5^2007*126
=126(5+5^2+5^3+...+5^2007) chia hết cho 126
=>S chia hết cho 126
\(A=\frac{5^{60}+1}{5^{61}+1}\)
\(5A=\frac{5(5^{60}+1)}{5^{61}+1}=\frac{5^{61}+5}{5^{61}+1}=\frac{5^{61}+1+4}{5^{61}+1}=1+\frac{4}{5^{61}+1}\) \((1)\)
\(B=\frac{5^{61}+1}{5^{62}+1}\)
\(5B=\frac{5(5^{61})+1}{5^{62}+1}=\frac{5^{62}+5}{5^{62}+1}=\frac{5^{62}+1+4}{5^{62}+1}=1+\frac{4}{5^{62}+1}\) \((2)\)
Từ 1 và 2 \(\Rightarrow1+\frac{4}{5^{61}+1}>1+\frac{4}{5^{62}+1}\)
\(\Rightarrow5A>5B\)
Hay \(A>B\)
Vậy : ...
a) \(\frac{3x}{-4}=\frac{-9}{6}\)
=> \(\frac{-3x}{4}=\frac{-9}{6}\)
=> \(\frac{-3x}{4}=\frac{-3}{2}\)
=> \(\frac{-3x}{4}=\frac{-6}{4}\)
=> \(-3x=-6\)
=> \(x=\left(-6\right):\left(-3\right)=2\)
b) \(\frac{2}{x}=\frac{y}{10}=\frac{4}{-5}\)
=> \(\frac{2}{x}=\frac{y}{10}=\frac{-4}{5}\)
+) \(\frac{2}{x}=\frac{-4}{5}\)
=> \(\left(-4\right)\cdot x=2\cdot5\)
=> \(\left(-4\right)\cdot x=10\)
=> \(x=\frac{10}{-4}=\frac{-10}{4}=\frac{-5}{2}\)
+) \(\frac{y}{10}=\frac{-4}{5}\)
=> \(5\cdot y=-40\)
=> \(y=\left(-40\right):5=-8\)
Vậy \(x=-\frac{5}{2},y=-8\)
c) \(\frac{7}{-x}=\frac{5}{y}=\frac{2}{34}\)
=> \(\frac{-7}{x}=\frac{5}{y}=\frac{1}{17}\)
+) \(\frac{-7}{x}=\frac{1}{17}\Rightarrow x=\left(-7\right)\cdot17=-119\)
+) \(\frac{5}{y}=\frac{1}{17}\Rightarrow y=5\cdot17=85\)
Vậy \(x=-119,y=85\)
d) \(\frac{x^2}{4}=16\)
=> \(x^2=16\cdot4=64\)
=> \(x\in\left\{8;-8\right\}\)
e) \(\frac{3}{x^3}=\frac{4}{-36}\)
=> \(\frac{3}{x^3}=\frac{1}{-9}=\frac{-1}{9}\)
=> \(x^3=3:\left(-\frac{1}{9}\right)=-27\)
=> \(x=-3\)
Vậy x = -3
Ta có :
a) \(5^9:5^7+2^4.3-29.2012^0\)
\(=5^2+16.3-29.1\)
\(=25+48-29=44\)
b) \(\left[32+\left(-17\right)+\left(-15\right)+\left(-34\right)\right]+\left(-\left|-56\right|\right)\)
\(=\left[34-2-17-15-34\right]+\left(-56\right)\)
\(=\left[0-2-17-15\right]-56\)
\(=-34-56=-90\)
\(\left(50-6x\right).18=2^3.3^2.5\)
\(\Leftrightarrow\left(50-6x\right).18=360\)
\(\Leftrightarrow50-6x=360:18\)
\(\Leftrightarrow50-6x=20\)
\(\Leftrightarrow6x=50-20\)
\(\Leftrightarrow6x=30\)
\(\Leftrightarrow x=30:6\)
\(\Leftrightarrow x=5\)
Vậy...
( 50 - 6x ) x 18 = 360
=> 50 - 6x = 20
=> 6x = 70
=> x = 35 / 3
Vậy x = 35 / 3
( mình khoong viết hẳn phép tính , chỉ tính thôi , bạn tự suy luận nhé !!!!)
1,
-8.3 - 9:9 + 25 = 0
2,
x= 3
y= -10
x-y= 3+10 =13
3,
-415+ 34 - 83 - 34 + 415 - 37 = 120
\(\left(5^{34}\cdot126-5^{34}\right):5^{36}=\frac{126}{5^2}-\frac{1}{5^2}=\frac{125}{5^2}=5\)