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a,
5,3 - (-5,1)+(-5,3) + 4,9;
\(\begin{array}{l}= 5,3 + 5,1 +(-5,3)+4,9 = \left[ {5,3 + \left( { - 5,3} \right)} \right] + \left( {5,1 + 4,9} \right)\\ = 0 + 10 = 10\end{array}\)
b,
(2,7 - 51,4) - (48,6 - 7,3)
\(\begin{array}{l} = 2,7 - 51,4 - 48,6 + 7,3\\ = \left( {2,7 + 7,3} \right) - \left( {51,4 + 48,6} \right)\\ = 10 - 100 = - 90\end{array}\)
c,
2,5. (-0,124) + 10, 124 . 2,5
= 2,5.(-0,124+10,124)
= 2,5.10
= 25
a: =5,3+5,1-5,3+4,9=10
b: =2,7-51,4-48,6+7,3
=10-100=-90
c: =2,5(-0,124+10,124)=2,5x10=25
d: =6,3-6,3+4.9=4,9
e: =15,3-21,5-4,5=-10,7
a/\(2\frac{1}{3}=\frac{2.3+1}{3}=\frac{7}{3}\)
\(4\frac{2}{5}=\frac{4.5+2}{5}=\frac{22}{5}\)
\(3\frac{1}{4}=\frac{3.4+1}{4}=\frac{13}{4}\)
\(9\frac{5}{7}=\frac{9.7+5}{7}=\frac{68}{7}\)
\(11\frac{3}{10}=\frac{11.10+3}{10}=\frac{113}{10}\)
b/\(5\frac{2}{17}=\frac{5.17+2}{17}=\frac{87}{17}\)
\(3\frac{6}{23}=\frac{3.23+6}{23}=\frac{75}{23}\)
\(7\frac{4}{9}=\frac{7.9+4}{9}=\frac{67}{9}\)
\(121\frac{15}{100}=\frac{121.100+15}{100}=\frac{12115}{100}\)
\(8\frac{3}{7}=\frac{8.7+3}{7}=\frac{59}{7}\)
\(\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=2,5-9,3\)
\(=-6,8\)
a: =5,3-0,7-5,3=-0,7
b: =5,3-10+3,1+4,7
=10-10+3,1=3,1
c: =9+3,6-4,1+1,3
=9+0,8=9,8
d: =21/47+26/47+1/5+4/5
=1+1
=2
e: =3/8(58/3-33/3)
=3/8*25/3
=25/8
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=\left(3,1-2,5\right)-\left(3,1-2,5\right)\)
\(=3,1-2,5-3,1+2,5\)
\(=\left(3,1-3,1\right)+\left(2,5-2,5\right)\)
\(=0+0=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3\)
\(=\left(5,3-5,3\right)-\left(2,8+4\right)\)
\(=0-\left(2,8+4\right)\)
\(=-2,8-4=-6,8\)
A = (3,1 – 2,5) – (-2,5 + 3,1) = 3,1 – 2,5 + 2,5 – 3,1 = 0
B = (5,3 – 2,8) – (4 + 5,3) = 5,3 – 2,8 – 4 – 5,3
A=(3,1-2,5)-(-2,5+3,1)=3,1-2,5+2,5-3,1=0
B=(5,3-2,8)-(4+5,3)=5,3-2,8-4-5,3=-6,8
=(5,3-5,3)+(5,1+4,9)=10
10