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a) \(\frac{2}{3}x\times\frac{1}{2}=\frac{1}{10}\Rightarrow\frac{2}{3}x=\frac{1}{5}\Rightarrow x=\frac{3}{10}\)
1)\(25x+3\left(4-6x\right)=50\)
\(25x+12-18x=50\)
\(7x+12=50\)
\(7x=38\)
\(x=\frac{38}{7}\)
2)\(4\left(2x+3\right)+2\left(3x+1\right)=120\)
\(8x+12+6x+2=120\)
\(14x+14=120\)
\(14x=106\)
\(x=\frac{53}{7}\)
\(\Rightarrow4x+8-3+6x=7-2x-2\)
\(\Rightarrow4x+6x+2x=-8+3-2\)
\(\Rightarrow12x=-7\)
\(\Rightarrow x=\frac{-7}{12}\)
Vậy \(x=\frac{-7}{12}.\)
bạn hoàng thị ngọc ánh làm sai rồi
\(4.\left(x+2\right)-3\left(1-2x\right)=7-2\left(x+1\right)\)
\(\Rightarrow4x+8-3-6x=7-2x-2\)
\(\Rightarrow4x+2x-6x+8-3=5\)
\(\Rightarrow6x-6x+8=5+3\)
\(\Rightarrow6x-6x=8-8\)
\(\Rightarrow6x-6x=0\)
Ta có: \(\left(4,5-2x\right):\frac{3}{4}=1\frac{1}{3}\)
=> \(\left(4,5-2x\right):\frac{3}{4}=\frac{4}{3}\)
=> \(4,5-2x=1\)
=> \(2x=3,5\Rightarrow x=1,75\)
Vậy x=1,75
1+2-3-4+5+6-7-8+9+................+33
=1+(2-3-4+5)+(6-7-8+9)+............+(30-31-32+33)
=1+0+0+..............+0
=1
a) (-4).(-3).(-125).25.(-8)
=[(-4).25].[(-125).(-8)].(-3)
=(-100).1000.(-3)
=300000
b) 7.(-25).(-3)2.(-4)
=7.[(-25).(-4)].9
=7.100.9
=6300
a ) [ (-4) . 25 ] . [ (-125) . (-8) ] . (-3)
= -100 . 1000 . (-3)
= -100000 . (-3)
= 300000
b) 7 . ( -25) . 9 . (-4)
= (7 . 9) . [ (-25) . (-4)]
= 63 . 100
= 6300
\(3^{x+4}=9^{2x-1}\)
\(\Rightarrow3^{x+4}=3^{4x-2}\)
\(\Rightarrow x+4=4x-2\)
\(\Rightarrow3x=6\Rightarrow x=2\)
9/2 - 2x = 4/3 . 3/4
9/2 - 2x = 1
2x=9/2 - 1
2x=7/2
x=7/2 : 2
X=7/4
9/2 - 2x = 4/3 . 3/4
9/2 - 2x = 1
2x=9/2 - 1
2x=7/2
x=7/2 : 2
X=7/4