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* Trả lời:
\(\left(1\right)\) \(-3\left(1-2x\right)-4\left(1+3x\right)=-5x+5\)
\(\Leftrightarrow-3+6x-4-12x=-5x+5\)
\(\Leftrightarrow6x-12x+5x=3+4+5\)
\(\Leftrightarrow x=12\)
\(\left(2\right)\) \(3\left(2x-5\right)-6\left(1-4x\right)=-3x+7\)
\(\Leftrightarrow6x-15-6+24x=-3x+7\)
\(\Leftrightarrow6x+24x+3x=15+6+7\)
\(\Leftrightarrow33x=28\)
\(\Leftrightarrow x=\dfrac{28}{33}\)
\(\left(3\right)\) \(\left(1-3x\right)-2\left(3x-6\right)=-4x-5\)
\(\Leftrightarrow1-3x-6x+12=-4x-5\)
\(\Leftrightarrow-3x-6x+4x=-1-12-5\)
\(\Leftrightarrow-5x=-18\)
\(\Leftrightarrow x=\dfrac{18}{5}\)
\(\left(4\right)\) \(x\left(4x-3\right)-2x\left(2x-1\right)=5x-7\)
\(\Leftrightarrow4x^2-3x-4x^2+2x=5x-7\)
\(\Leftrightarrow-x-5x=-7\)
\(\Leftrightarrow-6x=-7\)
\(\Leftrightarrow x=\dfrac{7}{6}\)
\(\left(5\right)\) \(3x\left(2x-1\right)-6x\left(x+2\right)=-3x+4\)
\(\Leftrightarrow6x^2-3x-6x^2-12x=-3x+4\)
\(\Leftrightarrow-15x+3x=4\)
\(\Leftrightarrow-12x=4\)
\(\Leftrightarrow x=-\dfrac{1}{3}\)
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
\(\left|3x+4\right|=x+2\\ \Rightarrow\left[{}\begin{matrix}3x+4=x+2\left(x\ge-\dfrac{4}{3}\right)\\3x+4=-\left(x+2\right)\left(x< -\dfrac{4}{3}\right)\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}3x-x=2-4\\3x+x=-2-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=-2\\4x=-6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\left(tm\right)\\x=-\dfrac{6}{4}=-\dfrac{3}{2}\left(tm\right)\end{matrix}\right.\)
______________________
\(\left|5x-6\right|=4-x\\ \Rightarrow\left[{}\begin{matrix}5x-6=4-x\left(x\ge\dfrac{6}{5}\right)\\5x-6=-\left(4-x\right)\left(x< \dfrac{6}{5}\right)\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}5x+x=4+6\\5x-x=-4+6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}6x=10\\4x=2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{10}{6}=\dfrac{5}{3}\left(tm\right)\\x=\dfrac{2}{4}=\dfrac{1}{2}\left(tm\right)\end{matrix}\right.\)
________________________
\(\left|5-2x\right|=x-3\\ \Rightarrow\left[{}\begin{matrix}5-2x=x-3\left(x\le\dfrac{5}{2}\right)\\5-2x=-\left(x-3\right)\left(x>\dfrac{5}{2}\right)\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}-2x-x=-3-5\\-2x+x=3-5\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}-3x=-8\\-x=-2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{-8}{-3}=\dfrac{8}{3}\left(ktm\right)\\x=2\left(ktm\right)\end{matrix}\right.\)
\(\left|3-2x\right|=6+4x\\ \Rightarrow\left[{}\begin{matrix}3-2x=6+4x\left(x\le\dfrac{3}{2}\right)\\3-2x=-\left(6+4x\right)\left(x>\dfrac{3}{2}\right)\end{matrix}\right.\\\Rightarrow\left[{}\begin{matrix}4x+2x=3-6\\-2x+4x=-6-3\end{matrix}\right. \\ \Rightarrow\left[{}\begin{matrix}6x=-3\\2x=-9\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\left(tm\right)\\x=-\dfrac{9}{2}\left(ktm\right)\end{matrix}\right.\)
________________________
\(\left|6-3x\right|=3x\\ \Rightarrow\left[{}\begin{matrix}6-3x=3x\left(x\le2\right)\\6-3x=-3x\left(x>2\right)\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}3x+3x=6\\6=0\left(ktm\right)\end{matrix}\right.\\ \Rightarrow x=\dfrac{6}{6}=1\left(tm\right)\)