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9/2-1/2-1+3x=1/2+1/3
=)8/2-1+3x=5/6
=)3+3x=5/6
=)3x=5/6-3
=)3x=13/6
x=13/18
ta có: 9/2 - 1/2 - (1-3x)=1/2 + 1/3
<=>9/2 - 1/2 - (1-3x)=5/6
<=>1/2 - (1-3x) =9/2-5/6
<=>1/2 - (1-3x) =11/3
<=> 1 - 3x = 19/6
<=> 3x =13/6
<=> x =13/18
a) \(\left(3x-2^4\right).7^3=2.7^4\)\(\Leftrightarrow3x-2^4=2.7^4:7^3\)
\(\Leftrightarrow3x-16=2.7\)\(\Leftrightarrow3x-16=14\)\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=10\)
Vậy \(x=10\)
b) \(3x+4x=\left|-75\right|+23\)\(\Leftrightarrow7x=75+23\)
\(\Leftrightarrow7x=98\)\(\Leftrightarrow x=14\)
Vậy \(x=14\)
a) \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
=> \(3x\cdot7^3-2^4\cdot7^3=2\cdot7\cdot7^3\)
=> \(3x\cdot7^3=14\cdot7^3+16\cdot7^3\)
=> \(3x\cdot7^3=\left(14+16\right)\cdot7^3\)
=> \(3x\cdot7^3=30\cdot7^3\)
=> \(3x=30\)(bỏ hai vế 73)
=> \(x=10\)
Vậy x = 10
b) \(3x+4x=\left|-75\right|+23\)
=> \(7x=75+23\)
=> \(7x=98\)
=> \(x=14\)
Vậy x = 14
b:
=>x(y-3)+3(y-3)=17
=>(y-3)(x+3)=17
\(\Leftrightarrow\left(x+3,y-3\right)\in\left\{\left(1;17\right);\left(17;1\right);\left(-1;-17\right);\left(-17;-1\right)\right\}\)
hay \(\left(x,y\right)\in\left\{\left(-2;20\right);\left(14;4\right);\left(-4;-14\right);\left(-20;2\right)\right\}\)
a: =>x(2y+3)+2(2y+3)=5
=>(2y+3)(x+2)=5
\(\Leftrightarrow\left(2y+3;x+2\right)\in\left\{\left(1;5\right);\left(-1;-5\right);\left(5;1\right);\left(-5;-1\right)\right\}\)
hay \(\left(y,x\right)\in\left\{\left(-1;3\right);\left(-2;-7\right);\left(1;-1\right);\left(-4;-3\right)\right\}\)
\(\left(x+2\right)-2=0\)
\(\Rightarrow x+2-2=0\)
\(\Rightarrow x=0\)
\(\left(x+3\right)+1=7\)
\(\Rightarrow x+3+1=7\)
\(\Rightarrow x+4=7\)
\(\Rightarrow x=3\)
\(\left(3x-4\right)+4=12\)
\(\Rightarrow3x-4+4=12\)
\(\Rightarrow3x=12\)
\(\Rightarrow x=4\)
\(\left(5x+4\right)-1=13\)
\(\Rightarrow5x+4-1=13\)
\(\Rightarrow5x+3=13\)
\(\Rightarrow5x=10\)
\(\Rightarrow x=2\)
\(\left(4x-8\right)-3=5\)
\(\Rightarrow4x-8-3=5\)
\(\Rightarrow4x-11=5\)
\(\Rightarrow4x=16\)
\(\Rightarrow x=4\)
\(8-\left(2x+4\right)=2\)
\(\Rightarrow8-2x-4=2\)
\(\Rightarrow4-2x=2\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
\(7+\left(5x+2\right)=14\)
\(\Rightarrow7+5x+2=14\)
\(\Rightarrow9+5x=14\)
\(\Rightarrow5x=5\)
\(\Rightarrow x=1\)
\(5-\left(3x-11\right)=1\)
\(\Rightarrow5-3x+11=1\)
\(\Rightarrow16-3x=1\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=5\)
1) \(\left(2x-4\right)\cdot3x=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-4=0\\3x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=0\end{cases}}\)
2) \(\left(3x-9\right)\left(10-2x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}3x-9=0\\10-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=5\end{cases}}\)
\(3^{x+2}+3^x=10\)
\(3^x\cdot\left(3^2+1\right)=10\)
\(3^x\cdot\left(9+1\right)=10\)
\(3^x\cdot10=10\)
\(3^x=10:10\)
\(3^x=1\)
\(3^x=3^0\)
\(\Rightarrow x=0\)