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\(\dfrac{3}{8}\left(x-\dfrac{2}{3}\right)-\dfrac{2}{9}\left(3x-\dfrac{1}{2}\right)=-\dfrac{7}{36}\)
\(\Leftrightarrow\dfrac{3}{8}x-\dfrac{1}{4}-\dfrac{2}{3}x+\dfrac{1}{9}=-\dfrac{7}{36}\)
\(\Leftrightarrow\dfrac{-7}{24}x=-\dfrac{1}{18}\)\(\Leftrightarrow x=\dfrac{4}{21}\)
1) \(\left|4-2x\right|.\dfrac{1}{3}=\dfrac{1}{3}\)
\(\left|4-2x\right|=\dfrac{1}{3}:\dfrac{1}{3}\)
\(\left|4-2x\right|=\dfrac{1}{3}.3\)
\(\left|4-2x\right|=1\)
=>\(4-2x=\pm1\)
+)\(TH1:4-2x=1\) +)\(TH2:4-2x=-1\)
\(2x=4-1\) \(2x=4-\left(-1\right)\)
\(2x=3\) \(2x=4+1\)
\(x=3:2\) \(2x=5\)
\(x=1,5\) \(x=5:2\)
Vậy x=1,5 \(x=2,5\)
Vậy x=2,5
2) \(\left(-3\right)^2:\left|x+\left(-1\right)\right|=-3\)
\(9:\left|x+\left(-1\right)\right|=-3\)
\(\left|x+\left(-1\right)\right|=9:\left(-3\right)\)
\(\left|x+\left(-1\right)\right|=-3\)
=> \(x+\left(-1\right)\) sẽ không có giá trị nào ( Vì giá trị tuyệt đối luôn luôn lớn hơn hoặc bằng 0 )
Vậy x = \(\varnothing\)
\(1,\Leftrightarrow7x=42\Leftrightarrow x=6\\ 2,\Leftrightarrow36-4x=4\Leftrightarrow4x=32\Leftrightarrow x=8\\ 3,\Leftrightarrow3x=35\Leftrightarrow x=\dfrac{35}{3}\\ 4,\Leftrightarrow x-12=144\Leftrightarrow x=156\\ 5,\Leftrightarrow x-14=16\Leftrightarrow x=30\\ 6,\Leftrightarrow3x-24=\dfrac{148}{73}\Leftrightarrow3x=\dfrac{1900}{73}\Leftrightarrow x=\dfrac{1900}{219}\\ 7,\Leftrightarrow33+x=45\Leftrightarrow x=12\\ 8,Sai.đề\\ 9,\Leftrightarrow\left(x+9\right):2=39\Leftrightarrow x+9=78\Leftrightarrow x=69\\ 11,\Leftrightarrow2\left(x+7\right)=38\Leftrightarrow x+7=19\Leftrightarrow x=12\\ 13,\Leftrightarrow2\left(x-51\right)=66\Leftrightarrow x-51=33\Leftrightarrow x=84\)
\(15,\Leftrightarrow x-19=9\Leftrightarrow x=28\\ 17,\Leftrightarrow\left(x-3\right):2=48\Leftrightarrow x-3=96\Leftrightarrow x=99\\ 19,\Leftrightarrow0x=46\Leftrightarrow x\in\varnothing\\ 8,Sai.đề\\ 14,\Leftrightarrow2x=209\Leftrightarrow x=\dfrac{209}{2}\\ 16,\Leftrightarrow2x+6=157\Leftrightarrow2x=151\Leftrightarrow x=\dfrac{151}{2}\\ 18,\Leftrightarrow5\left(x+4\right)=100\Leftrightarrow x+4=20\Leftrightarrow x=16\\ 20,\Leftrightarrow\left(3x-5\right)^3=27=3^3\Leftrightarrow3x-5=3\Leftrightarrow x=\dfrac{8}{3}\)
a: =7/8:(2/9-18+1/36)-5/12
=-7/142-5/12=-397/852
b: =3/7(4/9+5/9:6/12)=2/3
c: =5^8(16/31-47/31)+1/3=-5^8+1/3
d: =7/2(3/8+5/8:4/15)=609/64
\(a)-36:x=\frac{30}{7}\)
\(\Rightarrow x=-36:\frac{30}{7}\)
\(\Rightarrow x=-36\cdot\frac{7}{30}\)
\(\Rightarrow x=\frac{-36\cdot7}{30}\)
\(\Rightarrow x=-\frac{126}{15}\)
\(b)\frac{2}{3}\cdot x-\frac{4}{8}=\frac{1}{8}\)
\(\Rightarrow\frac{2}{3}\cdot x=\frac{1}{8}+\frac{4}{8}\)
\(\Rightarrow\frac{2}{3}\cdot x=\frac{5}{8}\)
\(\Rightarrow x=\frac{5}{8}:\frac{2}{3}=\frac{15}{16}\)
\(c)\frac{2}{7}-\frac{8}{9}x=\frac{2}{3}\)
\(\Rightarrow\frac{8}{9}x=\frac{2}{7}-\frac{2}{3}\)
\(\Rightarrow\frac{8}{9}x=\frac{6}{21}-\frac{14}{21}\)
\(\Rightarrow\frac{8}{9}x=\frac{-8}{21}\)
\(\Rightarrow x=\frac{-8}{21}:\frac{8}{9}=\frac{-72}{168}=\frac{-3}{7}\)
d, Tự làm
\(\dfrac{3}{8}x-\dfrac{1}{4}-\dfrac{2}{3}x+\dfrac{1}{9}=\dfrac{7}{36}\)
=> \(\dfrac{3}{8}x-\dfrac{2}{3}x-\left(\dfrac{1}{4}+\dfrac{1}{9}\right)=\dfrac{7}{36}\)
=> \(\dfrac{-7}{24}x-\dfrac{5}{36}=\dfrac{7}{36}\)
=> \(\dfrac{-7}{24}x=\dfrac{1}{3}\)
=> \(x=\dfrac{-8}{7}\)