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Đề em ghi bị thiếu dấu ngoặc nhé, sửa lại đề và giải như vầy:
375 : {32 - [4 + (5.32 - 42)]} - 14
= 375 : {32 - [4 + (5.9 - 42)]} - 14
= 375 : {32 - [4 + (45 - 42)]} - 14
= 375 : [32 - (4 + 3)] - 14
= 375 : (32 - 7) - 14
= 375 : 25 - 14
= 15 - 14
= 1
a) \(142-\left[50-\left(2^3.10-2^3.5\right)\right]\)
= \(142-\left[50-\left(8.10-8.5\right)\right]\)
= \(142-\left[50-8.\left(10-5\right)\right]\)
= \(142-\left[50-8.5\right]\)
= \(142-\left[50-40\right]\)
= \(142-10\)
= \(132\)
b) \(375:\left\{32-\left[4+\left(5.3^2-42\right)\right]\right\}-14\)
= \(375:\left\{32-\left[4+\left(5.9-42\right)\right]\right\}-14\)
= \(375:\left\{32-\left[4+\left(45-42\right)\right]\right\}-14\)
= \(375:\left\{32-\left[4+3\right]\right\}-14\)
= \(375:\left\{32-7\right\}-14\)
= \(375:25-14\)
= \(15-14\)
= \(1\)
Chúc bạn học tốt !!!
a) 142 - [ 50 - ( 23 . 10 - 23 . 5 )]
= 142 - [ 50 - ( 8 . 10 - 8 . 5 )]
= 142 - [ 50 - ( 80 - 40 )]
= 142 - [ 50 - 40 ]
= 142 - 10
= 132
b) 375 : { 32 - [ 4 + ( 5 . 32 - 42 )]} - 14
= 375 : { 32 - [ 4 + ( 5 . 9 - 42 )]} - 14
= 375 : { 32 - [ 4 + ( 45 - 42 )]} - 14
= 375 : { 32 - [ 4 + 3 ]} - 14
= 375 : { 32 - 7 } - 14
= 375 : 25 - 14
= 15 - 14
= 1
\(375\div\left\{32-\left[4+\left(5\times3^2-42\right)\right]\right\}-14\)
\(=375\div\left\{32-\left[4+3\right]\right\}-14\)
\(=375\div\left\{32-7\right\}-14\)
\(=375\div25-14\)
\(=15-14\)
\(=1\)
Chúc bạn học tốt!!!
\(375\div\left\{32-\left[4+\left(5\times3^2-42\right)\right]\right\}-14\)
= 375 : { 32 - [ 4 + 3 ]} - 14
= 375 : { 32 - 7 } - 14
= 375 : 25 - 14
= 15 - 14
= 1
Chúc bạn học tốt!!!
\(375:\left\{32-\left[4+\left(5.32-42\right)\right]\right\}-14\)
\(=375:\left\{32-\left[4+\left(160-42\right)\right]\right\}-14\)
\(=375:\left\{32-\left[4+118\right]\right\}-14\)
\(=375:\left\{32-122\right\}-14\)
\(=375:\left(-90\right)-14\)
\(=\dfrac{-25}{6}-14\)
\(=\dfrac{-109}{6}\)
a) `27 .75 + 25.27 -150`
`=27 xx (75 + 25)-150`
`=27 xx 100-150`
`=2700-150`
`=2550`
b) `142-[50-(2^3 .10-2^3 .5)]`
`=142-[50-2^3 .(10-5)]`
`=142-(50-8 .5)`
`=142-(50-40)`
`=142-10`
`=132`
c) `375:{32-[4+(5.3^2-42)]}-14`
`=375:{32-[4+(45-42)]}-14`
`=375:[32-(4+3)]-14`
`=375: 25 -14`
`=15-14`
`=1`
a. 27 . 75 + 25 . 27 - 150
= 27. (75 + 25) - 150
= 27 . 100 - 150
= 2700 - 150
= 2550
b. 142 - [50 - (23.10 - 23.5)]
= 142 - [50 - (8 . 10 - 8 . 5)]
= 142 - {50 - [8 . (10 - 5)]}
= 142 - (50 - 40)
= 142 - 10
= 132
c. 375 : {32 – [ 4 + (5. 32 – 42)]} – 14
= 375 : {32 – [ 4 + (5. 9 – 42)]} – 14
= 375 : {32 – [ 4 + (45 – 42)]} – 14
= 375 : {32 – [ 4 + 3]} – 14
= 375 : {32 –7} – 14
= 375 : 25 - 14
= 15 - 14
= 1
a: Ta có: \(142-\left[50-\left(2^3\cdot10-2^3\cdot5\right)\right]\)
\(=142-\left[50-80+40\right]\)
=142-10
=132
a. 142 - [50-(23.10-23.5)]
= 142 - [ 50 - ( 8 . 10 - 8 . 5 )]
= 142 - [ 50 - ( 80 - 40 )]
= 142 - [ 50 - 40 ]
= 142 - 10 = 132
b. 375 : { 32[ 4+(5.32 - 42 )]} - 14
= 375 : { 32[4+(5.9 - 42 )]} - 14
= 375 : { 32[4 + ( 45 - 42 )]} - 14
= 375 : {32[4+3]} - 14
= 375 : 224 - 14
c.{210 : [ 16+3.(6+3.2^2)]} - 3
= {210 : [ 16 + 3.(6+3.4)]} - 3
= { 210 :[16+3.(6+12)]}-3
= {210 : [ 16+3.18)]} - 3
= { 210 : [ 16 + 54]} - 3
= { 210 : 70 } - 3
= 30 - 3 = 27
d.500-{5.[409-(2^3 . 3-21^2)] - 1724}
= 500-{5.[409-(8 . 63 - 21^2] - 1724}
= 500 - { 5.[409- (504 - 441) - 1724}
= 500 -{ 5.[ 409 - 63 ] - 1724}
= 500 - { 5.346 - 1724}
= 500 - { 1720 - 1724 }
= 500 - 6
= 494
\(375:\left\{32-\left[4+\left(5.3^2-42\right)\right]\right\}\)
\(=375:\left\{32-\left[4+\left(45-42\right)\right]\right\}=375:\left\{32-\left[4+3\right]\right\}=375:\left\{32-7\right\}\)
=\(375:25=15\)
\(375:\left\{32-\left[4+\left(5.3^2-42\right)\right]\right\}\)
\(=375:\left\{32-\left[4+\left(45-42\right)\right]\right\}\)
\(=375:\left\{32-\left[4+3\right]\right\}\)
\(=375:\left\{32-7\right\}\)
\(=375:25\)
\(=15\)