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a ) 42.13 + 22.15 - 42.3 - 22.5
= 42 . 13 - 42.3 + ( 22.15 - 22. 5 )
= 42 . ( 13 - 3 ) + 22. ( 15 - 5 )
= 42. 10 + 22 . 10
= 10. ( 42 + 22 )
= 10 . 64
= 6400
b ) 24 . 42 - 35. 24 - 24.7
= 24. ( 42 - 35 - 7 )
= 24 . 0
= 0
19.64+76.34 35.12+65.13
=19.64+19.4.34 =35.12+65.(12+1)
=19.64+19.136 =35.12+65.12+65.1
=19.(64+136) =35.12+65.12+65
=19.200 =12.(35+65)+65
=3800 =12.100+65
=1200+65
=1265
\(\dfrac{12}{6.7}+\dfrac{12}{7.22}+\dfrac{12}{22.15}+\dfrac{12}{15.38}+...+\dfrac{12}{97.202}\)
\(=12.\left(\dfrac{1}{6.7}+\dfrac{1}{7.22}+\dfrac{1}{22.15}+\dfrac{1}{15.38}...+\dfrac{1}{97.202}\right)\)
\(=12.\left(\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{22}+\dfrac{1}{22}-\dfrac{1}{15}+...+\dfrac{1}{97}-\dfrac{1}{202}\right)\)
\(=12.\left(\dfrac{1}{6}-\dfrac{1}{202}\right)\)
\(=\dfrac{196}{101}\)
\(D=12\cdot\left(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{22}+...+\frac{1}{97}-\frac{1}{202}\right)\)
\(D=12\cdot\left(\frac{1}{6}-\frac{1}{202}\right)\)
\(D=12\cdot\frac{49}{303}\)
\(D=\frac{588}{303}\)
36.33-105.11+22.15
=1188-1155+330
=33+330
=363
\(36\cdot33-105\cdot11+22\cdot15\)
\(=11\cdot\left(36\cdot3-105+2\cdot15\right)\)
\(=11\cdot\left(108-105+30\right)\)
\(=11\cdot33\)
\(=33\cdot\left(10+1\right)\)
\(=330+33\)
\(=363\)